When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew = uF (b) What is the new potential difference between two plates? Vnew = volts (c) Find the energy stored in the new capacitor. Unew =
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- (a) When a 3.00-V battery is connected to the plates of a capacitor, it stores a charge of 19.0 µC. What is the value of the capacitance? μF (b) If the same capacitor is connected to a 15.0-V battery, what charge is stored? μCA 140 pF capacitor is charged to a potential difference of 74 V, and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the measured potential difference across the first capacitor drops to 25 V, what is the capacitance of this second capacitor?Two air-filled parallel-plate capacitors with capacitances C1 and C2 are connected in parallel to a battery that has a voltage of 36.0 V; C1 = 4.00 mF and C2 = 6.00 mF. (a) What is the total positive charge stored in the two capacitors? (b) While the capacitors remain connected to the battery, a dielectric with dielectric constant 5.00 is inserted between the plates of capacitor C1, completely filling the space between them. Then what is the total positive charge stored on the two capacitors? Does the insertion of the dielectric cause the total charge stored to increase or decrease?
- A 5.0 μ F capacitor is connected to a 12-volt ideal battery. While the battery is connected, a dielectric (κ = 2) is inserted into the capacitor. What is the charge on the capacitor?A parallel-plate capacitor has square plates that are 7.60 cm on each side and 4.00 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 7.60 cm on a side and 2.00 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 88.0 V, find how much electrical energy (in nJ) can be stored in this capacitor. 16.5662 × njA parallel-plate capacitor is charged by a 16.0 V battery, then the battery is removed. What is the potential difference between the plates after a sheet of Teflon is inserted between them?
- A parallel-plate capacitor has square plates that have edge length equal to 1.20×10^2cm and are separated by 1.00 mm. It is connected to a battery and is charged to 12.0 V. 1)How much energy is stored in the capacitor? (Express your answer to three significant figures.)An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.40 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pCA parallel-plate capacitor has capacitance 6.60 μF. (a) How much energy is stored in the capacitor if it is connected to a 1.50 V battery? (b) If the battery is disconnected and the distance between the charged plates doubled, what is the energy stored? Note: When disconnected, the charge on the capacitor must remain the same as when disconnected. (c) The battery is subsequently reattached to the capacitor, but the plate separation remains doubled as in part (b). How much energy is stored?
- A parallel-plate capacitor under the key of a keyboard has circular plates that are separated by 0.0500 mm and filled with a dielectric with k = 4.00. When the potential difference across the plates is 5.00 V , the magnitude of the charge on each plate is 8.897 pC. What is the radius of one of the plates? When the key is pressed, the distance between the plates decreases, increasing the capacitance to 1.85 pF. What is the separation between the plates when the key is pressed?(a) What is the capacitance of a parallel plate capacitor with metal plates, each of area 1 m², separated by 1.2 mm? Use & 8.85x10-¹² F/m. = C: (b) What charge is stored in this capacitor if a voltage of 2.5 × 10³ V is applied to it? Use Eo =8.85X10 F/m. -12 nF μСIn the figure the battery has a potential difference of V = 10.0 V and the five capacitors each have a capacitance of 9.00 uF. What is the charge on (a) capacitor 1 and (b) capacitor 2? FF (a) Number i (b) Number i Units Units