When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew = uF (b) What is the new potential difference between two plates? Vnew = volts (c) Find the energy stored in the new capacitor. Unew =

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YSY
When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the
distance between two parallel plates is now reduced to half.
(a) What is its new capacitance?
Cnew
µF
%3D
(b) What is the new potential difference between two plates?
Vnew
volts
(c) Find the energy stored in the new capacitor.
Unew
%3D
Transcribed Image Text:MY YSY When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew µF %3D (b) What is the new potential difference between two plates? Vnew volts (c) Find the energy stored in the new capacitor. Unew %3D
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