Answered: Dry air is a pretty decent insulator;… | bartleby

Related questions

Question

13
Dry air is a pretty decent insulator; it has a very high resistivity of 3 × 10º Q · m. Consider a
capacitor that has square plates 15 cm on a side, separated by 0.8 mm of dry air. The capacitor is
charged such that it has a potential of 320 V between the plates.

How much charge is stored on the plates of this capacitor when fully charged (in nC to 2 significant
digits)?

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

(a )A researcher connects a 3.00 V battery to the plates of a capacitor. After waiting a while, the capacitor reaches a maximum amount of 16.0 µC of stored charge. What is the value of the capacitance (in µF)? µF (b) The capacitor is disconnected from the battery, discharged, and then connected to a 10.0 V battery. Again, a long enough time is waited for the capacitor to fully charge. How much charge (in µC) is stored now? (Assume the capacitor can handle this new voltage without failing.) µC
An air-filled parallel-plate capacitor has a capacitance of 20.2μFμF. How much charge, in microcoulombs, must leak off its plates before the voltage across them is reduced by 125 V?
A 0.40 µF and a 0.60 µF capacitor are connected in series to a 9.0 V battery. Calculate (a) the potential difference across each capacitor and (b) the charge on each. (c) Repeat parts a & b assuming the two capacitors are in parallel.
You are given a box of 1000 capacitors. Each capacitor has a capacitance of 10 nF and can withstand a maximum potential difference of 5.0 V each. You are given the task of designing a network of capacitors that can with stand a potential difference of 15 V, but with an equivalent capacitance of 10 nF using only the capacitors provided. You may use as many of the capacitors (well, up to 1000..) as you need, but to save money you should use the fewest number that will meet the requirements. Sketch your network in the space below. Indicate the points at which this network would attach to the potential difference.
To repair a power supply for a stereo amplifier, an electronics technician needs a 100-μF capacitor capable of withstanding a potential difference of 90 V between the plates. The immediately available supply is a box of five 100-μF capacitors, each having a maximum voltage capability of 50 V. (a) What combination of these capacitors has the proper electrical characteristics? Will the technician use all the capacitors in the box? Explain your answers. (b) In the combination of capacitors obtained in part (a), what will be the maximum voltage across each of the capacitors used?
Problem 3: Consider a parallel plate capacitor having plates of area 1.65 cm2 that are separated by 0.024 mm of neoprene rubber. You may assume the rubber has a dielectric constant κ = 6.7. Part (a) What is the capacitance in nanofarads? Part (b) What charge, in coulombs, does the capacitor hold when 9.00 V is applied across it?
Two capacitors C1 = 6.20 μF and C2 = 14.4 μF are connected in series across a 15.0-Volt battery. They are carefully disconnected so that they are not discharged and are reconnected to each other (but not the battery) in parallel with positive plate to positive plate and negative plate to negative plate. Find the charge on C1 after the capacitors are reconnected. (I keep getting 9.3*10-5, 3.09*10-4, and 6.501*10-5 but none of them are correct) Find the final energy stored in C1.
A parallel plate capacitor is composed of two rectangular plates with length 5mm and width 3 mm. The thickness of the insulating material is 0.5 mm. Find the permittivity of the insulating material if the capacitance is 2 μF.
A parallel-plate capacitor has plates of area 0.12 m2 and a separation of 1.2 cm. A battery charges the plates to a potential difference of 120 V and is then disconnected. A dielectric slab of thickness 4.0 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab?
A capacitor of capacitance 400 µF is charged so that the potential difference between its plates is 5 V. How much charge (in mC) is transferred?
Two parallel plate capacitors, C₁ and C₂, are connected in series with a 65.0-V battery and a 290-k resistor, as shown in the figure. Both capacitors have plates with an area of 2.31 cm² and a separation of 0.170 mm. Capacitor C₁ has air between its plates, and capacitor C₂ has the gap filled with porcelain (dielectric constant of 7 and dielectric strength of 5.70 kV/mm). The switch is closed, and a long time passes. a) What is the charge on capacitor C₁? Submit Answer Tries 0/100 b) What is the charge on capacitor C₂? Submit Answer Tries 0/100 c) What is the total energy stored in the two capacitors? Submit Answer Tries 0/100 d) What is the electric field inside capacitor C₂? Submit Answer Tries 0/100 R + Vemf C₁ I C₂
To provide the pulse of energy needed for an intense bass, some car stereo systems add capacitors. One system uses a 2.0 F capacitor charged to 24 V, double the normal 12 V provided by the car’s battery. How much energy does the capacitor store at 12 V? At 24 V?

SEE MORE QUESTIONS