**Transcription for Educational Website:**---### Experimental Analysis of a Chemical Reaction Using 1H NMR Spectroscopy**Problem Statement:**You run the following reaction in the lab and take a \( ^1H \) NMR spectrum of the product. Determine the structure of the product. Did an \( S_N1 \) or \( E_1 \) reaction occur?**Reaction:**\[ \text{Reactant:} \, \text{A benzene ring attached to a secondary alcohol} \]Reagents: - \( \text{H}_2\text{SO}_4 \)- \( \text{CH}_3\text{OH} \)**NMR Spectrum Analysis:**- **Chemical Shifts (in ppm):** - **Around 7-8 ppm:** A set of multiple peaks representing the protons on the aromatic benzene ring, typically downfield due to the electronic environment. - **Around 3-4 ppm:** A single peak likely indicating the presence of a methoxyl (-OCH3) group or similar electron-withdrawing group environment. - **Around 1-2 ppm:** Multiple peaks suggesting protons from methyl (CH3-) or methylene (CH2-) groups in an alkyl chain or nearby structures.**Graphical Interpretation:**The spectrum displays several distinct regions:1. **Aromatic Region (7-8 ppm):** Corresponds to the aromatic protons, confirming the presence of a benzene ring in the product.2. **Methoxy Region (3-4 ppm):** Likely confirms a methoxy group in the structure, suggesting that a methyl ether formation may have occurred through an \( S_N1 \) reaction.3. **Aliphatic Region (1-2 ppm):** Indicates protons from methyl or methylene groups, further supporting the structure of the reaction product.**Conclusion:**Based on the \( ^1H \) NMR spectrum, the reaction likely proceeds via an \( S_N1 \) mechanism, resulting in the substitution product where the hydroxyl group has been replaced by an ether linkage due to the presence of methanol. This aligns with the characteristic peaks observed for aromatic protons, the methoxy group, and aliphatic protons.---This transcription provides a clear framework for understanding the reaction and interpreting the NMR data to deduce the product structure.

The reaction involved the formation of a carbocation intermediate. So it can be called an SN1 reaction though an H migration step is involved as shown below.The given H NMR spectrum supports the product shown above. In the below spectrum the H atoms where appears are marked i.e. their chemical shift values are marked.