Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw all possible elimination products for the following
Transcribed Image Text:### Educational Content on Organic Reactions
In this educational module, we explore three reactions involving alkyl halides and a base that potentially lead to elimination reactions.
#### Reaction 1:
- **Reactant:** A linear, six-carbon alkyl chain with a bromine atom (Br) attached to the terminal carbon.
- **Reagent:** Base
- **Process:** The structure shows an arrow indicating a reaction in the presence of a base. This suggests an elimination reaction, typically yielding an alkene.
#### Reaction 2:
- **Reactant:** A five-carbon chain with a methyl group on the second carbon and a bromine atom attached to the third carbon.
- **Reagent:** Base
- **Process:** The reaction proceeds with the addition of a base, likely resulting in a beta-elimination (E2 mechanism) to form an alkene.
#### Reaction 3:
- **Reactant:** A cyclohexane ring with a bromine atom attached to one of the carbons.
- **Reagent:** Base
- **Process:** The base likely induces a dehydrohalogenation reaction, converting the cyclohexyl bromide into a cyclohexene.
### Diagrams
Each of these reactions is diagrammed as starting materials undergoing a transformation in the presence of a base. The diagrams illustrate potential sites for elimination, emphasizing the role of the base in abstracting a proton adjacent to the carbon with the bromine, facilitating the formation of double bonds in the respective products.
Expert Solution
Step 1
First form carbocation and if posiible then rearrange it and remove H+ to form double bond.
In 1 and 2 two possibility
In 3 molecule 3 possibilities.
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