CONTENTS OF REACTION CUVETTES: (Calculations in PreLab)[ONPG]Diluted ONPG0mMNone0.25mL0.5mL0.75mL1.0mL bloo1.25mL1.5mLBufferLactase0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL*** HINT: To calculate [ONPG], cuvette #5 contains 1.0mL ONPG in a total of 2.0mL. (This is the same as a 1:2dilution.) Therefore we divide the concentration of ONPG by 2 to get 5mM.5mMWater1.5mL1.25mL1.0mL0.75mL0.5mL0.25mLNone***4. To perform Lactase Assay with first cuvette ("OmM"):Clean cuvette with Kimwipe.Place cuvette into Spectro Vis with stripes in front in back.GET GROUP READY FOR TIMED ASSAY. AT THE SAME TIME:* Press Record (Green Triangle button).* Add 0.25mL of Lactase to cuvette. Use pipette to quickly mix liquid.WAIT 60 SECONDS! After the assay is complete:* In Experiment menu, select "Store Latest Run" THIS STEP IS NECESSARY!* Record data on the data table below.5. Repeat Step 7 for all of your cuvettes. Record the data below.2viiboloV\:8A11201 201sall rade5. What is the final ONPG concentration (in mM) of each of the Reaction tubes?***Hint: Use the table on in your lab manual to figure this out. ***k moHatesgoutmM of ONPG in Reaction tube= 0mL of ONPG in a total volume of 2mL = 0 (10mM) = 0mM= 0.25 mL of ONPG in a total volume of 2mL = (0.25*10mM)/2 = 1.25mMmL of ONPG in a total volume of 2mL = (______ *10mM)/2 =mM== 1.0mL of ONPG in a total volume of 2mL = ½ (10mm) = 5mMMacBook Pro

The dilution formula is used to calculate the concentration of a solution after it has been diluted.…

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Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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When K > 1, which of the following statements is/are definitely TRUE? I. Products are favored II. ΔG for the reaction is positive III. kfwd > krev IV. the reaction is exothermic
As part of good experimental design, what are some other potential variables that we held constant among all four initial tubes? List at least four. View keyboard shortcuts
3a) An 68 kg patient is to be given a 2.0 mg/kg body weight IV bolus dose of a newly developed antibiotic drug every 6 hours. Assume the half-life of the drug and its volume of distribution in the patient are 3.2 hours and 0.26 L/kg respectively. (a) Calculate the peak and trough plasma concentrations for the antibiotic after, one dose, two doses, four doses, and at steady state.
Given the following data, determine the rate law for the reaction below. 2H2 (g) + 2NO(g) → 2H2O(g) + N2(g) Experiment 1 23 [H2] (M) [NO] (M) Initial Rate (M/s) 0.0369 0.0262 0.0248 0.1107 0.0262 0.0774 0.0369 0.0524 0.0992 Rate = k[H2][NO] Rate = k[H2][NO] Rate = k[NO]2 Rate = k[H2][NO]² Rate = k[H2][NO]
Fill up the two missing values inside the two circles knowing that the total reaction volume is 2mL. 1) Dilution fraction 2) Water Don't include units in your answer. Membrane Brillant blueR 1g/L Dilution Sample suspension fraction (μL) (μL) 1) Control ? 0 50 2) 1/200 ? 10 50 3) 1/100 0.01 20 50 4) 1/50 ? 40 50 5) 1/20 100 50 Phosphate pH11, 0.2M (ml) 1 1 1 1 1 Water (mL) 0.95 ? ? ?
It takes 175ml of 0.75 M H2SO4 to completely neutralize 285 ml of NaOH. What is the concentration of the NaOH solution?
24. Determine equilibrium constants for the hydrolysis of phosphoenolpyruvate (AG" is 61.9 kJ/mol) at pH 7 and 25°C: nariw (d)
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5. Anesthetic gases used in surgery are known to bind to the hemoglobin molecule in red blood cells. The diagram below illustrates O2 binding curves of normal human HbA in the presence of the anesthetic gas dichloromethane (DCM). O UNTREATED 100 a Dсм 23 Torr Symbols: в Dсм 50 Torr x DCM I00 Torr o, 0 Torr DCM; O, 23 Torr DCM A, 50 Torr DCM x, 100 Torr DCM. 80 60 40 (1 Torr = 1 mm Hg.) 20 The solutions were buffered to pH 7.4. 0.5 1.0 1.5 2.0 log p02 (a) (* Hill plots. Label the axes and indicate on both the plot above and the Hill plot where the value of the dissociation equilibrium constant Ka for O2 binding is defined for 0 and 100 Torr of dichloromethane For the curves at 0 and 100 Torr of dichloromethane, draw their equivalent in the form of Kd Hb(O2)n Hb + nO2 % OXYGENATION
3. Show the calculation of (1) the expected grams of alum (KAI(SO4)2 12 H2O) formed from the reaction of 1.4 grams of aluminum metal and then show the calculation of (2) the % yield if the actual yield of alum is 21.31 grams. Overall reaction is shown below: 2 Al + 2 KOH + 10 H2O + 4 H2SO4 →2 KAI(SO4)2 12 H2O + 3 H2(g)T

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