Are these reactions possible? ### Reaction 5**Reactant:** The structure is that of 3-methylbutan-2-ol, an organic compound featuring a branched-chain alcohol. The hydroxyl group (OH) is attached to the second carbon of the chain, which also has a side methyl group attached to the third carbon.**Reagent:** Sodium borohydride (NaBH₄) is the reagent used, along with methanol (CH₃OH) as the solvent.**Transformation:** This setup typically indicates a reduction process, although with primary and secondary alcohols, NaBH₄ will not normally be used for further reduction since they are already fully reduced forms in terms of the carbon-oxygen moiety.### Reaction 6**Reactant:** The structure is a cyclohexanol with an additional hydroxyl group (OH) attached to a side chain extending from the cyclohexane ring.**Reagent:** Sodium borohydride (NaBH₄) and methanol (CH₃OH) are employed.**Transformation:** Similarly, this setup is indicative of a reduction reaction. However, for secondary alcohols like cyclohexanol, NaBH₄ does not normally lead to further reduction of the alcohol functional group.### ExplanationBoth diagrams showcase typical setups for reaction conditions involving sodium borohydride. NaBH₄ is chiefly used for reducing aldehydes and ketones to alcohols but is shown here with alcohol reactants. The presence of methanol (CH₃OH) as a solvent ensures the solubility of NaBH₄, aiding in homogeneous conditions for reactions where NaBH₄ can be used.

Sodium borohydride is a very good reducing agent. It used for the reduction of the carbonyl compound to alcohol. The sodium borohydride is a selective reducing agent and it selectively reduces the carbonyl compound in the presence of other functional groups.Alcohols cannot reduce further into alkene by the sodium borohydride. Hence sodium borohydride cannot reduce the alcohol. The reaction of sodium borohydride can be explained as follows:Hence we can conclude that the alcohols do not react with NaBH4 and the given reaction is not possible.