Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![**Question 5:**
**Prompt:** Draw the mechanism used and the product.
**Chemical Reaction Details:**
- Starting Material: A benzene ring attached to a two-carbon chain that has a bromine (Br) atom on the first carbon. The second carbon is also bonded to two methyl groups (CH₃).
- Reagents:
- CH₃OH (methanol)
- Heat: 100°C
**Explanation:**
This is likely a nucleophilic substitution reaction involving methanol as the nucleophile. The reaction occurs under thermal conditions.
**Mechanism Explanation:**
1. **Nucleophilic Attack:** The methanol (CH₃OH) acts as a nucleophile and attacks the carbon atom bonded to bromine. This action displaces the bromine atom, forming a carbocation as an intermediate step.
2. **Bromine Departure:** The bromine leaves as a bromide ion (Br⁻), resulting in the formation of a new compound where the methanol group is attached to the same carbon that bromine was bonded to before.
3. **Product Formation:** The final product is an ether where the benzene ring is attached via a two-carbon chain to a methoxy group.
The reaction results in the substitution of the bromine atom with a methoxy group, forming a more stable ether product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6b4bd3b-c23c-4e19-9ff7-b724dd0e50b1%2Faba4bd45-5af2-4114-aa5b-c3d230a39e23%2Fmsh3gbj_processed.jpeg&w=3840&q=75)
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