5. Calculate the AH of the reaction of solid aluminum and gaseous chlorine to produce solid aluminum chloride. Use the equations below: Al(s) + 3HCI(aq) –→ AICI3(aq) + 1.5 H2(g) AH = -524.5 kJ %3D HCI(g) → HCI(aq) AH = -74.8 kJ %3D H2(g) + C12(g) → 2HCI(g) AH = -1845. kJ %3D AICI3(s) → AICI3(aq) AH = -323. kJ

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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5. Calculate the AH of the reaction of solid
aluminum and gaseous chlorine to produce
solid aluminum chloride. Use the equations
below:
Al(s) + 3HCI(aq) –→ AICI3(aq) + 1.5 H2(g)
AH = -524.5 kJ
%3D
HCI(g) → HCI(aq)
AH = -74.8 kJ
%3D
H2(g) + Cl2(g) → 2HCI(g)
AH = -1845, kJ
%3D
AICI3(s) → AICI3(aq)
AH = -323. kJ
Transcribed Image Text:5. Calculate the AH of the reaction of solid aluminum and gaseous chlorine to produce solid aluminum chloride. Use the equations below: Al(s) + 3HCI(aq) –→ AICI3(aq) + 1.5 H2(g) AH = -524.5 kJ %3D HCI(g) → HCI(aq) AH = -74.8 kJ %3D H2(g) + Cl2(g) → 2HCI(g) AH = -1845, kJ %3D AICI3(s) → AICI3(aq) AH = -323. kJ
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