½ N2(g) + %O2(g) = NO (g) = NO2(8) = N2O4 (g) From the following series of reactions find the free energy of formation of N204(g) at 25°C: AG°298K = 20, 720 cal AG°298K = -8330 cal AG°298K = -1380 cal %3D NO (g) + ½ O2 (g) 2NO2 (g)

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