5. A solution prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing 8.24 ug S/mL, and diluting to 50.0 mL. The measured signal quotient was (signal due to X/signal due to S) = 1.90/1.000. In a separate experiment it was found that, for equal concentrations of X and S, the signal quotient was (signal due to X/signal due to S) = 0.930/1.000. Find the concentration of X in the unknown. а. b. Answer the same question if in a separate experiment it was found that for the concentration of X equal to 3.42 times the concentration of S, the signal quotient was (signal due to X/signal due to S) = 0.930/1.000.

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5. A solution prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S)
containing 8.24 µg S/mL, and diluting to 50.0 mL. The measured signal quotient was (signal
due to X/signal due to S) = 1.90/1.000.
a. In a separate experiment it was found that, for equal concentrations of X and S, the signal
quotient was (signal due to X/signal due to S) = 0.930/1.000. Find the concentration of X
in the unknown.
b. Answer the same question if in a separate experiment it was found that for the
concentration of X equal to 3.42 times the concentration of S, the signal quotient was
(signal due to X/signal due to S) = 0.930/1.000.
Transcribed Image Text:5. A solution prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing 8.24 µg S/mL, and diluting to 50.0 mL. The measured signal quotient was (signal due to X/signal due to S) = 1.90/1.000. a. In a separate experiment it was found that, for equal concentrations of X and S, the signal quotient was (signal due to X/signal due to S) = 0.930/1.000. Find the concentration of X in the unknown. b. Answer the same question if in a separate experiment it was found that for the concentration of X equal to 3.42 times the concentration of S, the signal quotient was (signal due to X/signal due to S) = 0.930/1.000.
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