5. A quality control engineer found that the inner and outer diameters of their ball bearings, denoted respectively as X and Y, are random variables with E(X|Y = y) = 0.7-0.3y inches and Var(X|Y = y) = 0.0004y for all values of y. From his past experience he also knew that the mean and variance of the outer diameters were E(Y) = (0.7 inches, and Var(Y) = 0.0001 squared inches. %3D (i) What are the conditional random variables, E(X Y) and Var(X|Y)? • (ii) Find the mean of the inner diameters, E(X). • (iii) Find the variance of the inner diameters, Var(X).
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- Suppose it is desired to estimate the variance of the tensile strength of a particular type of thread. For 21 pieces of this type of thread, E (X; – Xave)² = 2000. Suppose a hypothesis testing procedure is wished to be carried out to check whether or not it is safe to assume that the variability in tensile strength of thread is 110. Derive the condition that needs to be satisfied, expressed in terms of the value of s? (sample variance), such that the null hypothesis will be accepted. (Use 0.05 level of significance.) What is the maximum value of s? such that we still accept tensile strength variability to be 110?Imagine that there is a correlation of r = 0.65 between variable X and variable Y. Based on the correlation between these two variables (and only these two variables), what is a person's predicted value on variable Y, when his X value on variable X is a z score of 1.5? Please provide your answer as a z score with a minimum of three decimal places.Consider the variable X whose mean and variance are given respectively by μx = 28.4 and Var(X) =8.6. Next consider the variable Y such that Y = 18.6 X-52 What is the mean of variable Y?
- A random sample of n1 = 20 winter days in Denver gave a sample mean pollution index x1 = 43. Previous studies show that ?1 = 11. For Englewood (a suburb of Denver), a random sample of n2 = 18 winter days gave a sample mean pollution index of x2 = 36. Previous studies show that ?2 = 15. Assume the pollution index is normally distributed in both Englewood and Denver. Do these data indicate that the mean population pollution index of Englewood is different (either way) from that of Denver in the winter? Use a 1% level of significance. a) What is the value of the sample test statistic? (Test the difference ?1 − ?2. Round your answer to two decimal places.)b) Find (or estimate) the P-value. (Round your answer to four decimal places.)The engineer of large manufacturing company takes many measurements of a specific dimension of components from the production line. She finds that the distribution of dimensions is approximately normal, with a mean of 3.33 cm and a coefficient of variation of 3.60%. i. What percentage of measurements will be less than 3.50 cm? What percentage of dimensions will be between 3.10 cm and 3.50 cm? What percentage of measurements will be equal to 3.50 cm? What value of the dimension will be exceeded by 90% of the components? ii. iii. iv.A weight-loss program wants to test how well their program is working. The company selects a simple random sample of 51 individual that have been using their program for 15 months. For each individual person, the company records the individual's weight when they started the program 15 months ago as an x-value. The subject's current weight is recorded as a y-value. Therefore, a data point such as (205, 190) would be for a specific person and it would indicate that the individual started the program weighing 205 pounds and currently weighs 190 pounds. In other words, they lost 15 pounds. When the company performed a regression analysis, they found a correlation coefficient of r = 0.707. This clearly shows there is strong correlation, which got the company excited. However, when they showed their data to a statistics professor, the professor pointed out that correlation was not the right tool to show that their program was effective. Correlation will NOT show whether or not there is…
- Consider the following data points, where the first coordinate corresponds to x and the second coordinate corresponds to y (0.1) (1.1) (2.0) (3,7) Observe there is a missing value (?). It is known that: • the variance of b, is equal to 0.25 • the t-statistic associated to b, is equal -0.8 (this is, minus 0.8) Compute the Adjusted r Squared (Enter your answer to one decimal place. For "0.9", you would write 0.9). Do not round.7)Suppose that weights of college mathematics textbooks in the United States are normally distributed with mean µ = 2.25 lbs and variance σ2 = 0.2025 lbs. Find the weight that corresponds to Q3 and interpret this measure of position in the context of the problem.
- Psi is a measure of compressive strength, or the ability of the material to carry loads and handle compression. The desired concrete psi rating used for sidewalks and residential driveways ranges from 2500psi to 3000psi obtained from mixing cement, stone, and sand in different ratios but with the same amount of water. The summary of the psi's of three (3) such concrete mixes made by three (3) different civil engineering students is given as follows: Mean vector: The variance-covariance matrix: Concrete mix Mean Concrete mix 1 Concrete mix 2 Concrete mix 3 Concrete mix 1 | Concrete mix 2 2700 18 12 2 3000 12 16 3 2400 Concrete mix 3 16 25 Let the random variable Y be the vector of the psi's of concrete mixes obtained by the students, i.e. Y1, denotes the psi of concrete mix made by student 1, Y2 is the psi of concrete mix made by student 2 and Y3 is the psi of concrete mix psi made by student 3. (a) Find (i) the multivariate probability distribution function (pdf) of Y. (ii) the…Suppose ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 113.3, s₁=5.01, n = 9, y = 129.6, and s₂ = 5.34. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT -21.57 1x ) Does the interval suggest that precise information about the value of this difference is available? Because the interval is so narrow, it appears that precise information is available. Because the interval is so narrow, it appears that precise information is not available. Because the interval is so wide, it appears that precise information is available. Because the interval is so wide, it appears that precise information is not available. x -11.06