Please help me complete question 5 and 6 **Table: Results of Heat Capacity Trials**| Trial | Substance | Mass (grams) | ΔT (°C) | Added Energy (Joules) ||-------|-----------|--------------|---------|-----------------------|| 1 | Hg | 100.0 | 71.0 | 1,000.0 || 2 | Hg | 100.0 | 142 | 2,000.0 || 3 | H₂O | 100.0 | 2.39 | 1,000.0 || 4 | H₂O | 100.0 | 4.78 | 2,000.0 |**Explanation:**This table represents the results of experiments conducted to measure the temperature change (ΔT) of two substances, Mercury (Hg) and Water (H₂O), when a specific amount of energy is added. Each trial uses a 100-gram sample of the substance.- **Trial 1 and 2**: Mercury is subjected to 1,000 and 2,000 Joules of energy respectively. The resulting temperature changes are 71.0°C and 142°C.- **Trial 3 and 4**: Water is subjected to 1,000 and 2,000 Joules of energy respectively. The resulting temperature changes are 2.39°C and 4.78°C.This illustrates the different specific heat capacities of the two substances, where a smaller temperature change in water indicates a higher specific heat capacity compared to mercury. **5. Problem Statement:**"If 20,000 J of energy are used to heat mercury by 4.00 °C, what is the mass of mercury?"---**6. Problem Statement:**"Determine the specific heat of aluminum if adding 4,750 kJ of heat energy to 249.0 g of aluminum produces a temperature change of 21.1 °C."

Heat released or absorbed by a substance is calculated as: q = m.C.∆T where m is the mass of the substance, C is the specific heat of the substance, ∆T is the temperature change5. Firstly, determine the specific heat capacity of mercury from the given table, Use data from Trial 1, C = qm.∆T= 1000 J(100 g) × (71.0 Co)= 0.141 J/g.Co Given data: q = 20000 J, ∆T = 4.00 oC m = qC.∆T= 20000 J(0.141 J/g.C)o (4.00 C)o= 35461.0 g Hence, mass of mercury = 35461.0 g6. Given data: m = 249.0 g, q = 4.750 kJ = 4750 J ∆T = 21.1 oC C = qm.∆T= 4750 J(249 g) × (21.1 Co)= 0.904 J/g.Co Hence, specific heat of Aluminum = 0.904 J/g oC