(5) This simply-supported beam has been subjected to an applied moment at midspan. The M(x) equations have been supplied for you. You are to write the v(x) equations for 0≤x≤ L/2 and for L/2≤ x₂ L Fair warning. This is a very challenging problem. It is also a sort of a Mechanics of Materials "rite of passage." This beam has two M(x) functions so there will be four constants of integration. You must solve for all four. Two of the four are related to slope compatibility and deflection compatibility at x=L/2. The easiest way to solve this problem is by using some "bonus" boundary conditions that relate to anti-symmetry. Good luck. M x1. -4/2 + x₁ X₂ V₁ DM₁ Mo 4/2+
(5) This simply-supported beam has been subjected to an applied moment at midspan. The M(x) equations have been supplied for you. You are to write the v(x) equations for 0≤x≤ L/2 and for L/2≤ x₂ L Fair warning. This is a very challenging problem. It is also a sort of a Mechanics of Materials "rite of passage." This beam has two M(x) functions so there will be four constants of integration. You must solve for all four. Two of the four are related to slope compatibility and deflection compatibility at x=L/2. The easiest way to solve this problem is by using some "bonus" boundary conditions that relate to anti-symmetry. Good luck. M x1. -4/2 + x₁ X₂ V₁ DM₁ Mo 4/2+
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Ans. V =
Mo
24ET
3
[4x_xt]
;
%
=
3
Mo
Wez [ 4% - 2x + 11 %2 -3]
?
3L²
24ET](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf84dde2-f77b-4203-b744-f3414691451c%2F7e4c88a2-ed2f-49b7-85dc-d5cdb3927c8d%2Fwv9dnkl_processed.png&w=3840&q=75)
Transcribed Image Text:Ans. V =
Mo
24ET
3
[4x_xt]
;
%
=
3
Mo
Wez [ 4% - 2x + 11 %2 -3]
?
3L²
24ET
Transcribed Image Text:(5) This simply-supported beam has been subjected to an applied
moment at midspan. The M(x) equations have been supplied for
you. You are to write the v(x) equations for 0<x< L/2 and for
L/2<x₂≤L.
Fair warning. This is a very challenging problem. It is also a sort
of a Mechanics of Materials "rite of passage." This beam has two
M(x) functions so there will be four constants of integration. You
must solve for all four. Two of the four are related to slope
compatibility and deflection compatibility at x=L/2. The easiest
way to solve this problem is by using some "bonus" boundary
conditions that relate to anti-symmetry. Good luck.
r|3
M
x1
HAT
-4/2-+
x₁
x2
JM,
x2
M₂ = Moxa - Mo
Mo
-4/2-+
Mo
M₂
M₁ = M₂x₁
L
DRAW V(X) HERE
Mo
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