5 The circuit of Figure P5.35 is a simple model of an automotive ignition system. The switch models the "points" that switch electric power to the cylinder when the fuel-air mixture is compressed. And Ris the resistance between the electrodes (1.e., the “gap") of the spark plug. Vc = 12 V Rc = 0.37 2 R= 1.7 k2 Determine the value of L and R¡ so that the voltage across the spark plug gap just after the switch is changed is 23 kV and so that this voltage will change exponentially with a time constant t = 13 ms. t= 0 RG RŽVR Ri VG L.

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Author:Robert L. Boylestad
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5 The circuit of Figure P5.35 is a simple model of an
automotive ignition system. The switch models the
"points" that switch electric power to the cylinder
when the fuel-air mixture is compressed. And Ris the
resistance between the electrodes (1.e., the “gap") of
the spark plug.
Vc = 12 V
Rc = 0.37 2
R= 1.7 k2
Determine the value of L and R¡ so that the voltage
across the spark plug gap just after the switch is
changed is 23 kV and so that this voltage will change
exponentially with a time constant t = 13 ms.
t= 0
RG
RŽVR
Ri
VG
L.
Transcribed Image Text:5 The circuit of Figure P5.35 is a simple model of an automotive ignition system. The switch models the "points" that switch electric power to the cylinder when the fuel-air mixture is compressed. And Ris the resistance between the electrodes (1.e., the “gap") of the spark plug. Vc = 12 V Rc = 0.37 2 R= 1.7 k2 Determine the value of L and R¡ so that the voltage across the spark plug gap just after the switch is changed is 23 kV and so that this voltage will change exponentially with a time constant t = 13 ms. t= 0 RG RŽVR Ri VG L.
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