5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, www cell potential, find the value of E. E°Mg2+/Mg -2,37 V; E°Ag+/Ag = 0,800 V %3D %3D
5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, www cell potential, find the value of E. E°Mg2+/Mg -2,37 V; E°Ag+/Ag = 0,800 V %3D %3D
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![5)
One silver electrode in 246 mL of 0.100 M AGNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2
solution
A galvanic cell was formed by dipping the magnesium electrode.
a)
E value of the cell at 25 ° C calculate.
wwww
b)
Since the current is generated at the silver electrode until 2.10 g of silver is collected,
cell potential, find the value of E.
E°Mg2+/Mg = -2,37 V; E°Ag+/Ag = 0,800 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2b2072f-78f3-4b0f-8d67-5aa07dafac06%2F4512ae04-4e19-49e1-86b6-8dba621ba2b4%2Fo8cudn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5)
One silver electrode in 246 mL of 0.100 M AGNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2
solution
A galvanic cell was formed by dipping the magnesium electrode.
a)
E value of the cell at 25 ° C calculate.
wwww
b)
Since the current is generated at the silver electrode until 2.10 g of silver is collected,
cell potential, find the value of E.
E°Mg2+/Mg = -2,37 V; E°Ag+/Ag = 0,800 V
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