5)One silver electrode in 246 mL of 0.100 M AGNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2solutionA galvanic cell was formed by dipping the magnesium electrode.a)E value of the cell at 25 ° C calculate.wwwwb)Since the current is generated at the silver electrode until 2.10 g of silver is collected,cell potential, find the value of E.E°Mg2+/Mg = -2,37 V; E°Ag+/Ag = 0,800 V

Answered: Image /qna-images/answer/4512ae04-4e19-49e1-86b6-8dba621ba2b4.jpg

5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, www cell potential, find the value of E. E°Mg2+/Mg -2,37 V; E°Ag+/Ag = 0,800 V %3D %3D

5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, www cell potential, find the value of E. E°Mg2+/Mg -2,37 V; E°Ag+/Ag = 0,800 V %3D %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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