5) Now let's move on to Heaps... Given a max heap implementation, draw the heap after each of the following operations is processed. Begin with an empty heap (Heap H;). a. H. Insert (14); d. H. Insert (32); b. H. Insert (40); e. H.Insert (12); c. H. Insert (26); f. H. Insert (45); g. H. Insert (28); h. H. Insert (9); i. H. Insert (8); j. H. Insert (16); k. H. Remove (); 1. H. Remove ();
5) Now let's move on to Heaps... Given a max heap implementation, draw the heap after each of the following operations is processed. Begin with an empty heap (Heap H;). a. H. Insert (14); d. H. Insert (32); b. H. Insert (40); e. H.Insert (12); c. H. Insert (26); f. H. Insert (45); g. H. Insert (28); h. H. Insert (9); i. H. Insert (8); j. H. Insert (16); k. H. Remove (); 1. H. Remove ();
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![5) Now let's move on to Heaps...
Given a max heap implementation, draw the heap after each of the following operations is processed.
Begin with an empty heap (Heap H;).
a. H. Insert (14); d. H. Insert (32);
b. H. Insert (40);
c. H. Insert (26);
e. H. Insert (12);
f. H. Insert (45);
g. H. Insert (28);
h. H.Insert (9);
i. H. Insert (8);
j. H. Insert (16);
k. H. Remove ();
1. H. Remove ();](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa51e933b-ba3d-42c9-b6cc-7bf0377c4bf9%2F07f95c8a-be84-45be-9c96-cc48ebad741b%2Fnazo5h_processed.png&w=3840&q=75)
Transcribed Image Text:5) Now let's move on to Heaps...
Given a max heap implementation, draw the heap after each of the following operations is processed.
Begin with an empty heap (Heap H;).
a. H. Insert (14); d. H. Insert (32);
b. H. Insert (40);
c. H. Insert (26);
e. H. Insert (12);
f. H. Insert (45);
g. H. Insert (28);
h. H.Insert (9);
i. H. Insert (8);
j. H. Insert (16);
k. H. Remove ();
1. H. Remove ();
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