5 Let F(t) = 4t*i + 2 sin(5t) j+ 3e“k and G(t) = - (cos(3t)) i – j+ k , find F(t) · G(t). ( 10 sin(5t) А. + 3e* ) i - (20 + 3e* cos(3t)) j + (-4tt + 2 sin(5t) cos(3t)) k t4 15e4t В. — 4t4 сos(3t) i - 2 sin(5t)j + -k 15et с. — 4t сos(3t) — 2 sin(5t) + t4 15et -4t“ cos(3t) – 2 sin(5t) + t4 D. 10 sin(5t) E. + 3et – (20 + 3e“ cos(3t)) + (-4t“) +2 sin(5t) cos(3t) t4
5 Let F(t) = 4t*i + 2 sin(5t) j+ 3e“k and G(t) = - (cos(3t)) i – j+ k , find F(t) · G(t). ( 10 sin(5t) А. + 3e* ) i - (20 + 3e* cos(3t)) j + (-4tt + 2 sin(5t) cos(3t)) k t4 15e4t В. — 4t4 сos(3t) i - 2 sin(5t)j + -k 15et с. — 4t сos(3t) — 2 sin(5t) + t4 15et -4t“ cos(3t) – 2 sin(5t) + t4 D. 10 sin(5t) E. + 3et – (20 + 3e“ cos(3t)) + (-4t“) +2 sin(5t) cos(3t) t4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Let F(t) = 4t*i + 2 sin(5t) j+ 3e“k and G(t) = - (cos(3t)) i – j+ k , find F(t) · G(t).
10 sin(5t)
А.
e)i- (20+3e cos(3t)) j + (-4tª + 2 sin(5t) cos(3t)) k
В. — 414 cos(3t)і — 2 sin(st) j +
15et
-k
t4
15e4t
с. — 4t сos(3t) — 2 sin(st) +
t4
15e4t
-4t“ cos(3t) – 2 sin(5t) +
j
t4
D.
10 sin(5t)
+ 3et – (20 + 3e“ cos(3t)) + (-4t“) + 2 sin(5t) cos(3t)
t4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ad1ba9b-19b0-4473-bce3-71a3387972dd%2Fc9b0f8e2-77e2-499b-bd0c-64ca43f3f345%2F9kp20du_processed.png&w=3840&q=75)
Transcribed Image Text:Let F(t) = 4t*i + 2 sin(5t) j+ 3e“k and G(t) = - (cos(3t)) i – j+ k , find F(t) · G(t).
10 sin(5t)
А.
e)i- (20+3e cos(3t)) j + (-4tª + 2 sin(5t) cos(3t)) k
В. — 414 cos(3t)і — 2 sin(st) j +
15et
-k
t4
15e4t
с. — 4t сos(3t) — 2 sin(st) +
t4
15e4t
-4t“ cos(3t) – 2 sin(5t) +
j
t4
D.
10 sin(5t)
+ 3et – (20 + 3e“ cos(3t)) + (-4t“) + 2 sin(5t) cos(3t)
t4
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