For sin(u/2), cos(u/2), and tan(u/2) given cos(u)=-sqrt2/3 and sin(u)>0 I got sin(u/2)=sqrt(3+sqrt2)/sqrt6 cos(u/2)=sqrt(3-sqrt2)/sqrt6 tan(u/2)=sqrt(3+sqrt2)/sqrt(3-sqrt2) Are these correct?
For sin(u/2), cos(u/2), and tan(u/2) given cos(u)=-sqrt2/3 and sin(u)>0 I got sin(u/2)=sqrt(3+sqrt2)/sqrt6 cos(u/2)=sqrt(3-sqrt2)/sqrt6 tan(u/2)=sqrt(3+sqrt2)/sqrt(3-sqrt2) Are these correct?
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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For sin(u/2), cos(u/2), and tan(u/2) given cos(u)=-sqrt2/3 and sin(u)>0
I got sin(u/2)=sqrt(3+sqrt2)/sqrt6
cos(u/2)=sqrt(3-sqrt2)/sqrt6
tan(u/2)=sqrt(3+sqrt2)/sqrt(3-sqrt2)
Are these correct?
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