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(1 point) Approximate cos(4.6) using a quadratic approximat First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)

(1 point) Approximate cos(4.6) using a quadratic approximat First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)
Transcribed Image Text:(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)
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