5 find dy/dx for y= [(r^2+1)] ^(-1) ,x= [(4r+1)] ^(1/2) (use chain rule) 5-find for y= (r² + 1)~1 „x = (4r + 1)½ (use chain nule) dx Vr+1 A) %3D dx (r2 +1) dy r(4r + 1) B)- dx %3D (r +1)2 rV4r +1 dy C) dx (r2+ 1)2 %3D Oa e Ob OC ارسال الاجابة

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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/ المادة : الرياضيات - سنوي
answer all the questions
5 find dy/dx for y= [(r^2+1)] ^(-1) ,x=
[(4r+1)] ^(1/2) (use chain rule)
dy
5-find for y (r2 + 1)x =
(4r + 1)½
(use chain nule)
dx
A)d
Vr+1
(r2+1)
%3D
dx
dy r(4r+ 1)
B):
(r +1)2
dx
dy TV4 +1
C)
(r2 + 1)2
dx
Oa e
Ob
Oc
ارسال الاجابة
السؤال السابق
السؤال التالي
Transcribed Image Text:/ المادة : الرياضيات - سنوي answer all the questions 5 find dy/dx for y= [(r^2+1)] ^(-1) ,x= [(4r+1)] ^(1/2) (use chain rule) dy 5-find for y (r2 + 1)x = (4r + 1)½ (use chain nule) dx A)d Vr+1 (r2+1) %3D dx dy r(4r+ 1) B): (r +1)2 dx dy TV4 +1 C) (r2 + 1)2 dx Oa e Ob Oc ارسال الاجابة السؤال السابق السؤال التالي
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