A cardioid is given by the equation x² + y² = (2x²+2y²-x)². Find the equation for the tangent line to the cardioid at the point (0,2). Hint: the algebra will be easier of you plug in your values (x, y) = (0, 1) before solving for (but after taking all derivatives). dy dx

Q: dy Find - by implicit differentiation. Jx + y +Vxy =4 dx

A: Given: x + y + xy = 4

Q: Given 3x²-5y³ = 4x² + y² - 7 find dy dx and d² dx² y at the point

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Q: use Substitution method to Schve (3メ -2Y +1)dx -(X-2Y-3)dy=o

A: The given differential equation is 3x-2y+1dx-x-2y-3dy=0.

Q: - 3x³)dy – (2y³ – x²y)dx -

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Q: 2) For the equation x + y = 1, find and simplify dy (a) dx d²y (b) dx²

A: Step 1: Step 2:

Q: Use implicit differentiation to determine dy dx = dy dx given the equation x² + y5 = 3.

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Q: dy Part II: Find the derivative ) implicitly. Show all work. dx 11. e" – 4x³ + 5y? = 10

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Q: y³ + x = x³ + xy. What are the values of dy/dx where y = 0.

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Q: Let 22 + y? = 45- dy -(6, 3) [The derivative at da the point (6, 3) ].

A: Given,           x2+y2=45

Q: 5

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