5) Calculate E cel at 313K for the concentration cell described below. Both electrodes are made or Mg. On the left side of the cell there is a solution of 0.10 M Mg(NO3)2. On the right side of the cell a saturated solution of MgF2 is prepared by adding 1.00 g of solid of MgF2 to 100.0 mL of pure water. Because Ksp for MgF2 is small (K, for MgF2=64 x 10"), the concentration of Mg²+ on the right side of the cell is much less than 0.10 M. Mg2+ + 2e Mg E° = -2.37 V Voltmeter Porous Mg Barrier Mg Saturated MgF2 0.10 M Mg(NO3)2

5) Calculate E cel at 313K for the concentration cell described below. Both electrodes are made or Mg. On the left side of the cell there is a solution of 0.10 M Mg(NO3)2. On the right side of the cell a saturated solution of MgF2 is prepared by adding 1.00 g of solid of MgF2 to 100.0 mL of pure water. Because Ksp for MgF2 is small (K, for MgF2=64 x 10"), the concentration of Mg²+ on the right side of the cell is much less than 0.10 M. Mg2+ + 2e Mg E° = -2.37 V Voltmeter Porous Mg Barrier Mg Saturated MgF2 0.10 M Mg(NO3)2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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