1. Consider the concentration cell below: Identify the anode, cathode, and the direction of electron flow. Calculate the cell potential at 25°C. The [Ag*] in the right-hand beaker is 1.0x10 8 М. I Ag- Ag [Ag']=1.0 M
1. Consider the concentration cell below: Identify the anode, cathode, and the direction of electron flow. Calculate the cell potential at 25°C. The [Ag*] in the right-hand beaker is 1.0x10 8 М. I Ag- Ag [Ag']=1.0 M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Concentration Cells and Electrochemical Potential: An Example
#### Problem Statement:
Consider the concentration cell below: Identify the anode, cathode, and the direction of electron flow. Calculate the cell potential at 25°C. The [Ag⁺] in the right-hand beaker is 1.0 x 10⁻⁸ M.
#### Detailed Diagram Description:
The diagram depicts a concentration cell consisting of two beakers connected by a salt bridge. Each beaker contains a silver electrode (denoted as Ag), immersed in solutions of different concentrations of Ag⁺ ions.
- **Left Beaker:** Contains an Ag electrode and a solution with Ag⁺ concentration of 1.0 M.
- **Right Beaker:** Contains an Ag electrode and a solution with Ag⁺ concentration of 1.0 x 10⁻⁸ M.
#### Key Points:
- **Anode and Cathode Identification:**
- Anode (oxidation will occur): The electrode in the less concentrated solution (right beaker, [Ag⁺] = 1.0 x 10⁻⁸ M).
- Cathode (reduction will occur): The electrode in the more concentrated solution (left beaker, [Ag⁺] = 1.0 M).
- **Direction of Electron Flow:**
- Electrons flow from the anode to the cathode. In this cell, electrons will flow from the right beaker to the left beaker.
- **Cell Potential Calculation:**
- Use the Nernst equation to calculate the potential of the concentration cell:
\[
E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{RT}{nF} \ln \frac{C_2}{C_1}
\]
- For silver electrodes, \( E^\circ_{\text{cell}} = 0 \) since the same material is in both electrodes.
- Simplified Nernst equation for concentration cell:
\[
E_{\text{cell}} = - \frac{RT}{nF} \ln \frac{[Ag^+]_{\text{right}}}{[Ag^+]_{\text{left}}}
\]
- At 25°C (298 K), \( \frac{RT}{F} \approx 0.0257 \) V:
\[
E_{\text{cell](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7c13c2cd-7092-4d54-837b-d1e36936f099%2F2bda1cf1-ad0c-4f9c-9c3d-d1565d029ff0%2Forwv3c.jpeg&w=3840&q=75)
Transcribed Image Text:### Concentration Cells and Electrochemical Potential: An Example
#### Problem Statement:
Consider the concentration cell below: Identify the anode, cathode, and the direction of electron flow. Calculate the cell potential at 25°C. The [Ag⁺] in the right-hand beaker is 1.0 x 10⁻⁸ M.
#### Detailed Diagram Description:
The diagram depicts a concentration cell consisting of two beakers connected by a salt bridge. Each beaker contains a silver electrode (denoted as Ag), immersed in solutions of different concentrations of Ag⁺ ions.
- **Left Beaker:** Contains an Ag electrode and a solution with Ag⁺ concentration of 1.0 M.
- **Right Beaker:** Contains an Ag electrode and a solution with Ag⁺ concentration of 1.0 x 10⁻⁸ M.
#### Key Points:
- **Anode and Cathode Identification:**
- Anode (oxidation will occur): The electrode in the less concentrated solution (right beaker, [Ag⁺] = 1.0 x 10⁻⁸ M).
- Cathode (reduction will occur): The electrode in the more concentrated solution (left beaker, [Ag⁺] = 1.0 M).
- **Direction of Electron Flow:**
- Electrons flow from the anode to the cathode. In this cell, electrons will flow from the right beaker to the left beaker.
- **Cell Potential Calculation:**
- Use the Nernst equation to calculate the potential of the concentration cell:
\[
E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{RT}{nF} \ln \frac{C_2}{C_1}
\]
- For silver electrodes, \( E^\circ_{\text{cell}} = 0 \) since the same material is in both electrodes.
- Simplified Nernst equation for concentration cell:
\[
E_{\text{cell}} = - \frac{RT}{nF} \ln \frac{[Ag^+]_{\text{right}}}{[Ag^+]_{\text{left}}}
\]
- At 25°C (298 K), \( \frac{RT}{F} \approx 0.0257 \) V:
\[
E_{\text{cell
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