5) Calculate AGrxn at 298 K under the conditions shown below for the following reaction. 5) 3 02(g) -2 O3(g) AG° = +326 kJ %3D P(O2) = 0.077 atm, P(O3) =0.61 atm

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Chapter 19 - Thermodynamics - x
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5) Calculate AGrxn at 298 K under the conditions shown below for the following reaction.
5)
3 02(g) -2 O3(g)
AG° = +326 kJ
P(O2) = 0.077 atm, P(O3) = 0.61 atm
6) Determine the equilibrium constant for the following reaction at 298 K.
6)
SO3(g) + H2O(g) – H2SO4(1)
AG° = -90.5 kJ
1
7) For a reaction Keg = 1.2x 10-6 at T = 200 K. What is AG for the reaction?
7)
hp
Transcribed Image Text:Chapter 19 - Thermodynamics - x kboardcdn.com/blackboard.learn.xythos.prod/5970c46bc1741/9717426?X-Blackboard-Expiration=1650261600000.. 2 * O*NET OnLine Ee Home | exploreheal. * Patient Portal - heal... 2.. Scholarships - SAL. * 20 Highest Paid No.. Om Access 1./2 100% 5) Calculate AGrxn at 298 K under the conditions shown below for the following reaction. 5) 3 02(g) -2 O3(g) AG° = +326 kJ P(O2) = 0.077 atm, P(O3) = 0.61 atm 6) Determine the equilibrium constant for the following reaction at 298 K. 6) SO3(g) + H2O(g) – H2SO4(1) AG° = -90.5 kJ 1 7) For a reaction Keg = 1.2x 10-6 at T = 200 K. What is AG for the reaction? 7) hp
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