5) A student wants to know the number of food Calories in their favorite snack. They burn their snack under a can of water to measure the energy transfer and record the following information: Mass of water: 200g Water temperature before burning (T.): 25°C. Water temperature after burning (T₁): 45°C. The Specific Heat (Cp) of water is 1 chemistry calorie/g °C a. Calculate the number of chemistry calories of Heat transferred to water using the following formula: Q= M * Cp * (T-T) b. The mass of the snack before burning was 2.0g and the mass after the snack burning was 1.0g. Calculate the number of chemistry calories per gram of the snack. c. There are 1000 chemistry calories per 1 food Calorie. Calculate the number of food Calories per gram of snack.

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### Calorimetry Experiment: Determining Food Calories in a Snack

#### Problem Statement:

A student wants to know the number of food Calories in their favorite snack. They burn their snack under a can of water to measure the energy transfer and record the following information:

- **Mass of water:** 200g
- **Water temperature before burning (Ti):** 25°C
- **Water temperature after burning (Tf):** 45°C
- **Specific Heat (Cp) of water:** 1 chemistry calorie/g °C

#### Tasks:

**a. Calculate the number of chemistry calories of Heat transferred to water using the following formula:**

\[ Q = M \times Cp \times (T_f - T_i) \]

where:
- \( Q \) = heat energy (in chemistry calories)
- \( M \) = mass of water (in grams)
- \( Cp \) = specific heat capacity of water (1 chemistry calorie/g °C)
- \( T_f \) = final temperature of water (in °C)
- \( T_i \) = initial temperature of water (in °C)

**b. The mass of the snack before burning was 2.0g and the mass after the snack burning was 1.0g. Calculate the number of chemistry calories per gram of the snack.**

**c. There are 1000 chemistry calories per 1 food Calorie. Calculate the number of food Calories per gram of snack.**

### Solution Guide 

**a. Calculating Heat Energy Transferred to Water**

Given:
- Mass of the water (\( M \)) = 200g
- Specific Heat (\( Cp \)) = 1 chemistry calorie/g °C
- Initial temperature (\( T_i \)) = 25°C
- Final temperature (\( T_f \)) = 45°C

Substitute these values into the formula:

\[ Q = M \times Cp \times (T_f - T_i) \]
\[ Q = 200 \, g \times 1 \, \text{chemistry calorie/g °C} \times (45°C - 25°C) \]
\[ Q = 200 \times 1 \times 20 \]
\[ Q = 4000 \, \text{chemistry calories} \]

Thus, 4000 chemistry calories of heat were transferred to the water.

**b. Calculating Chemistry Calories per Gram of the
Transcribed Image Text:### Calorimetry Experiment: Determining Food Calories in a Snack #### Problem Statement: A student wants to know the number of food Calories in their favorite snack. They burn their snack under a can of water to measure the energy transfer and record the following information: - **Mass of water:** 200g - **Water temperature before burning (Ti):** 25°C - **Water temperature after burning (Tf):** 45°C - **Specific Heat (Cp) of water:** 1 chemistry calorie/g °C #### Tasks: **a. Calculate the number of chemistry calories of Heat transferred to water using the following formula:** \[ Q = M \times Cp \times (T_f - T_i) \] where: - \( Q \) = heat energy (in chemistry calories) - \( M \) = mass of water (in grams) - \( Cp \) = specific heat capacity of water (1 chemistry calorie/g °C) - \( T_f \) = final temperature of water (in °C) - \( T_i \) = initial temperature of water (in °C) **b. The mass of the snack before burning was 2.0g and the mass after the snack burning was 1.0g. Calculate the number of chemistry calories per gram of the snack.** **c. There are 1000 chemistry calories per 1 food Calorie. Calculate the number of food Calories per gram of snack.** ### Solution Guide **a. Calculating Heat Energy Transferred to Water** Given: - Mass of the water (\( M \)) = 200g - Specific Heat (\( Cp \)) = 1 chemistry calorie/g °C - Initial temperature (\( T_i \)) = 25°C - Final temperature (\( T_f \)) = 45°C Substitute these values into the formula: \[ Q = M \times Cp \times (T_f - T_i) \] \[ Q = 200 \, g \times 1 \, \text{chemistry calorie/g °C} \times (45°C - 25°C) \] \[ Q = 200 \times 1 \times 20 \] \[ Q = 4000 \, \text{chemistry calories} \] Thus, 4000 chemistry calories of heat were transferred to the water. **b. Calculating Chemistry Calories per Gram of the
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