5 5 2 3 B # # v1: v2: This program gives you some practice w shift, and rotate operators main: .global .data .word .word .text .set .ent lw $s1, v1 12 main 0xFEEDABEE noreorder main ## $s1 v1 =
5 5 2 3 B # # v1: v2: This program gives you some practice w shift, and rotate operators main: .global .data .word .word .text .set .ent lw $s1, v1 12 main 0xFEEDABEE noreorder main ## $s1 v1 =
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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
Transcribed Image Text:This code illustrates a MIPS assembly program focusing on bitwise operations, shifts, and rotations. Below is the transcription and explanation:
```assembly
# This program gives you some practice working with bitwise,
# shift, and rotate operators
.global main
.data
v1: .word 12
v2: .word 0xFEEDABEE
.text
.set noreorder
.ent main
main:
lw $s1, v1 ## $s1 = v1
lw $s2, v2 ## $s2 = v2
## $t0 = v2 with highest 12 bits cleared (set to 0), other bits staying the same
## $t1 = v2 with lower 1 byte set to 1, other bits staying the same
## $t2 = v1 multiplied by 4 *without* using a multiply instruction
## $t3 = v2 divided by 7 *without* using a multiply instruction
## $t4 = remainder of v1 divided by 5
## $t5 = v2 with the lowest 6 bits flipped (inverted) and the upper 26 bits staying the same
## $t6 = 0x1401FED0 without using any pseudo-instructions (i.e., shouldn't use "li $t6, 0xABCD1357")
# This code simply loops infinitely
spin: j spin
nop
.end main
```
### Explanation of Operations:
- **Loading Values**:
- `$s1` is loaded with the value from `v1` (12).
- `$s2` is loaded with the value from `v2` (0xFEEDABEE).
- **Bitwise Operations**:
- `$t0` operation clears the highest 12 bits of `v2`.
- `$t1` sets the lower byte of `v2` to 1 while keeping the rest unchanged.
- `$t5` flips the lowest 6 bits of `v2` and retains the upper 26 bits.
- **Arithmetic Operations**:
- `$t2` computes `v1` * 4 without direct multiplication.
- `$t3` divides `v2` by 7 without using a direct division instruction.
Expert Solution
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