only question 5-10 part E please show all steps and indicate any reference charts or material please I am struggling to understand 5-9.FIGURE P5-8n5-9 to 5-17. Determine the OP, and Pne for each of the columns, using the AISC Specification50 ksi, unless noted otherwise.and Fya. W10 x 77 with Lc = KL 20 ft. (Ans. 548 k LRFD; 365 k ASD)b. Pipe 8 STD, F, = 35 ksi with Lc = KL = 18 ft. (Ans. 188 k LRFD; 125 k ASD)c. WT6 x 25 with Lc = KL = 12 ft. (Ans. 182 k LRFD; 121 k ASD)-77777775-11.5-10. Note that F, is different for parts (c) to (e)a. A W10 x 30 with pinned ends, L = 10 ft.b. An HP8 X 36 with fixed ends, L20 ft.c. An HSS 6 × 4 x 1/4, F, = 46 ksi with pinned ends, L = 12 ft.d. AW14 × 90, Fy = 36 ksi with one end fixed and the other end pinned, L = 30 ft.e. An HSS 4 x 0.250, 42 ksi with pinned ends, L= 10 ft.A W8 x 18 with a 1/4 x 6 cover plate welded to each flange is to be used for acolumn with KL = L = 14 ft. (Ans. 135.1 k, LRFD; 90.0 k, ASD)O

Solution: Calculate the effective length and slenderness ratio: Kx = ky = 1 (both ends are pinned:…

5-10. Note that F, is different for parts (c) to (e) a. A W10 x 30 with pinned ends, L = 10 ft. b. An HP8 X 36 with fixed ends, L = 20 ft. c. An HSS 6 x 4 x 1/4, F, 46 ksi with pinned ends, L = 12 ft. d. A W14 x 90, F, = 36 ksi with one end fixed and the other end pinned, L = 30 ft. e. An HSS 4 x 0.250, 42 ksi with pinned ends, L = 10 ft. =

5-10. Note that F, is different for parts (c) to (e) a. A W10 x 30 with pinned ends, L = 10 ft. b. An HP8 X 36 with fixed ends, L = 20 ft. c. An HSS 6 x 4 x 1/4, F, 46 ksi with pinned ends, L = 12 ft. d. A W14 x 90, F, = 36 ksi with one end fixed and the other end pinned, L = 30 ft. e. An HSS 4 x 0.250, 42 ksi with pinned ends, L = 10 ft. =

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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