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4x² dx2 3 +4x Y ² +(16x²– 1)y =x dx which has the following two linearly independent solution of the homogineous equation sin(2x) V2x The particular solution is given by. cos(2x) V2x Yolx) = cos(2x)sin(2x) 4/x Yp(x) = cos(2x) , sin(2x) V2x V2x Yox) = 2cos(2x)sin(2x) V2x O you) = Jo 2x

4x² dx2 3 +4x Y ² +(16x²– 1)y =x dx which has the following two linearly independent solution of the homogineous equation sin(2x) V2x The particular solution is given by. cos(2x) V2x Yolx) = cos(2x)sin(2x) 4/x Yp(x) = cos(2x) , sin(2x) V2x V2x Yox) = 2cos(2x)sin(2x) V2x O you) = Jo 2x

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Yp(x) = Cos(2x) , sin(2x) d²y 4x +4x Y +(16x²– 1)y =x ² dx? dx which has the following two linearly independent solution of the homogineous equation cos(2x) sin(2x) /2x The particular solution is given by. cos(2x)sin(2x) Yp(x) =. 1 Yp(x) = 4/x cos(2x) , sin(2x) /2x V2x Yox) = 2cos(2x)sin(2x) V2x 1 ° Yp(x) = 2x
Transcribed Image Text:Yp(x) = Cos(2x) , sin(2x) d²y 4x +4x Y +(16x²– 1)y =x ² dx? dx which has the following two linearly independent solution of the homogineous equation cos(2x) sin(2x) /2x The particular solution is given by. cos(2x)sin(2x) Yp(x) =. 1 Yp(x) = 4/x cos(2x) , sin(2x) /2x V2x Yox) = 2cos(2x)sin(2x) V2x 1 ° Yp(x) = 2x
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