We would like to find a formula for eax sin(bx) dx by completi eax sin(bx) dx u = sin(bx) = du = b cos(bx) dx 1 du = eax dx → v = -eax a 1 sin(bx) · -ex - eªx .b cos(bx) dx - a 1 edx sin(bx)- eax cos(bx) dx a Please continue with the work to show that the formula is eax eax sin(bx) dx = b cos(bx) + a sin(bx) + C - a2 + b2

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