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We would like to find a formula for eax sin(bx) dx by completi eax sin(bx) dx u = sin(bx) = du = b cos(bx) dx 1 du = eax dx → v = -eax a 1 sin(bx) · -ex - eªx .b cos(bx) dx - a 1 edx sin(bx)- eax cos(bx) dx a Please continue with the work to show that the formula is eax eax sin(bx) dx = b cos(bx) + a sin(bx) + C - a2 + b2

We would like to find a formula for eax sin(bx) dx by completi eax sin(bx) dx u = sin(bx) = du = b cos(bx) dx 1 du = eax dx → v = -eax a 1 sin(bx) · -ex - eªx .b cos(bx) dx - a 1 edx sin(bx)- eax cos(bx) dx a Please continue with the work to show that the formula is eax eax sin(bx) dx = b cos(bx) + a sin(bx) + C - a2 + b2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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We would like to find a formula for eax sin(bx) dx by completin eax sin(bx) dx u = sin(bx) = du b cos(bx) dx %D 1 U = -eax a du = eax dx = 1 sin(bx) · -ex ea. b cos(bx) dx - a a 1 -eax sin(bx) – - / e* cos(bx) dx a a Please continue with the work to show that the formula is eax sin(bx) dx = eax |- b cos(bx) + a sin(bx) + C a2 + b2
Transcribed Image Text:We would like to find a formula for eax sin(bx) dx by completin eax sin(bx) dx u = sin(bx) = du b cos(bx) dx %D 1 U = -eax a du = eax dx = 1 sin(bx) · -ex ea. b cos(bx) dx - a a 1 -eax sin(bx) – - / e* cos(bx) dx a a Please continue with the work to show that the formula is eax sin(bx) dx = eax |- b cos(bx) + a sin(bx) + C a2 + b2
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