+4% grade meets a -5% grade at sta 50+00. Using a 600 ft equal-tangent vertical curve, what is most nearly the distance from the point of vertical curvature (PVC) to the high point? A. 0.44 ft ahead from PVC B. 2.7 ft ahead from PVC C. 44 ft ahead from PVC D. 300 ft ahead from PVC

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: 1.    Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of…

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Q: answer question 18 only

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Q: An SVC connects a -4% grade to a +4% grade. The curve goes under a pedestrian bridge at PVI. The…

A: Given:Vertical clearanceSight distanceHeight of drivers eyeHeight of objectTo find: Length of curve.

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: Referring to the following illustration, a -4% grade meets a +5% grade at the point of vertical…

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Q: Q2) A proposed highway has two tangents of bearings N 45°54'36" E and N 1°22'30" W. The highway…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: comply with the SSD. 6. A grade g₁ of +3.50% intersects grade g₂ of -2.50% and an equal-tangent…

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Q: A +4.0% grade intersects a -3.0% percent grade al r two-lane highway with a design speed of 45 mph.…

A: Given: PVI station= 222+00 Elevation= 300.00 Design speed = V=45 mph   To determine: A) the minimum…

Q: 3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be…

A: I have tried to solve this problem and also write the given data in diagram plz have gone through it

Q: An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10…

A: Solution  Given That G1=+1.90%G2=-3.10%

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: 600-ft crest vertical curve is to be developed from a +1.80% grade intersecting with a -3.4% grade…

A: Given Initial grade = 1.8% Final grade = -3.4% Station PVI= 15+50= 1550ft Elevation of PVI= 315.76ft…

Q: Please explain the question.

A: Sag Vertical Curve

Q: A horizontal curve on Texas Highway 83 (Tx83) comprises of a two-lane rural highway with a lane…

A: Stopping Sight Distance: It is the minimum sight distance available at any spot having sufficient…

Q: owed by a 1.25% grade intersecting at Sta. 15+750, with an elevation of 374.5 m. The change of grade…

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Q: A highway has +2.0% grade followed by a -2.0% grade. The PVC is at STA(1033+58.00) and the PVT is at…

A: Following are the given data. A highway has +2.0% grade followed by a -2.0% grade. The PVC is at STA…

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A +2% grade intersects with a -1% grade at station (535-24.25) at an elevation of 300 ft. If the…

A: Solution:-Given,Elevation=300ftDesign speed=60 mi/hg1=2%g2=-1%

Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

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Q: Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph.…

A: Step 1:Step 2: Step 3: Step 4:

Q: What is the elevation of the low point of a curve that connects a grade of -1.1% to 1.5%, is 587…

A: The stationing of PVC = 55+25The elevation of PVC = 732 ftThe curve length, L = 587 ftThe curve…

Q: An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI…

A: