+4% grade meets a -5% grade at sta 50+00. Using a 600 ft equal-tangent vertical curve, what is most nearly the distance from the point of vertical curvature (PVC) to the high point? A. 0.44 ft ahead from PVC B. 2.7 ft ahead from PVC C. 44 ft ahead from PVC D. 300 ft ahead from PVC

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: 1.    Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of…

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Q: answer question 18 only

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Q: An SVC connects a -4% grade to a +4% grade. The curve goes under a pedestrian bridge at PVI. The…

A: Given:Vertical clearanceSight distanceHeight of drivers eyeHeight of objectTo find: Length of curve.

Q: Determine the importance of utilizing an S-Curve in the field of Construction

A: S curve is a graph which is in s shape which represents the cumulative cash and time periods of the…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: A grade of -1.2% joins a grade of 1.8% at station 23+40 which has an elevation of 209.04 ft.…

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Q: Referring to the following illustration, a -4% grade meets a +5% grade at the point of vertical…

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Q: A curve joins 0% grade with 12.5% grade. The point of intersection is at station 2+282.15 and…

A: PVCSTATION=PVISTA-L2PVCsta=2290.85-1582=2+211.85PVCELV=PVIELV-g1L2PVCelv=68.21+0×6502PVCelv=68.21

Q: Q2) A proposed highway has two tangents of bearings N 45°54'36" E and N 1°22'30" W. The highway…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: The gradients of two intersected grade line are -3% and 3%, the radius of vertical curve is 3000m,…

A: Given:- The gradients of two intersected grade lines are:- g1 = -3% g2 = 3% The radius of the…

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

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Q: 7.5% grade is followed by a 1.225% grade intersecting at Sta. 15+750, with an elevation of 395.5 m.…

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Q: comply with the SSD. 6. A grade g₁ of +3.50% intersects grade g₂ of -2.50% and an equal-tangent…

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Q: If + 0.8% grade meets - 0.7% grade and the rate of change of grade for 30 m distance is 0.05, the…

A: g2 = -0.7% g1 = 0.8%  Rate of change of grade r= 0.05/30 = 0.00167

Q: A parabolic curve has a descending grade of -0.88% which meets an ascending grade of 0.45% at sta.…

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Q: A +4.0% grade intersects a -3.0% percent grade al r two-lane highway with a design speed of 45 mph.…

A: Given: PVI station= 222+00 Elevation= 300.00 Design speed = V=45 mph   To determine: A) the minimum…

Q: A 777m equal tangent crest vertical curve has PVC at Sta 17+315 and at elevation 189m. The initial…

A: Given data- 777m equal tangent crest vertical curve. PVC at Sta 17+315 and at elevation 189m. The…

Q: elevation 400 m. Length of first curve is 180 m and that of the second curve is 120 m. What is the…

A: Given data grade, g1 =+4% grade, g2 =-2% elevation =400m Length of first curve = 180 m  Length of…

Q: 3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be…

A: I have tried to solve this problem and also write the given data in diagram plz have gone through it

Q: An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10…

A: Solution  Given That G1=+1.90%G2=-3.10%

Q: forward tangent is -3.0%, and the location of the highest point elevation of the highest point is…

A:

Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

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Q: 600-ft crest vertical curve is to be developed from a +1.80% grade intersecting with a -3.4% grade…

A: Given Initial grade = 1.8% Final grade = -3.4% Station PVI= 15+50= 1550ft Elevation of PVI= 315.76ft…

Q: Please explain the question.

A: Sag Vertical Curve

Q: A horizontal curve on Texas Highway 83 (Tx83) comprises of a two-lane rural highway with a lane…

A: Stopping Sight Distance: It is the minimum sight distance available at any spot having sufficient…

Q: A parabolic vertical curve joins a grade of -2.0% to a grade of 0.5%. The point of intersection of…

A: Soution: d = 390-300 = 90 m Eleve = 100-4 = 96 m Elevf = 0.5% of 90 = 0.45 Elevg = 2% of 90=1.8

Q: owed by a 1.25% grade intersecting at Sta. 15+750, with an elevation of 374.5 m. The change of grade…

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Q: A highway has +2.0% grade followed by a -2.0% grade. The PVC is at STA(1033+58.00) and the PVT is at…

A: Following are the given data. A highway has +2.0% grade followed by a -2.0% grade. The PVC is at STA…

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A 524m equal tangent crest vertical curve has PVC at Sta 18+257 and at elevation 166m. The initial…

A: Given: The initial grade is 6.06%. The final grade is -3.71%. The length is 524 m. The PVC station…

Q: A +2% grade intersects with a -1% grade at station (535-24.25) at an elevation of 300 ft. If the…

A: Solution:-Given,Elevation=300ftDesign speed=60 mi/hg1=2%g2=-1%

Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

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Q: A grade of +3% is followed by a grade of -1.6%. The point of intersection of the tangents is at…

A: A) Compute the stationing of the highest point of the curve. B) Compute the elevation of the highest…

Q: Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph.…

A: Step 1:Step 2: Step 3: Step 4:

Q: C-A -3% grade is connected to a +4% grade for a vertical curve. The PC. station is 00 and PC.…

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Q: PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3%   The…

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Q: What is the elevation of the low point of a curve that connects a grade of -1.1% to 1.5%, is 587…

A: The stationing of PVC = 55+25The elevation of PVC = 732 ftThe curve length, L = 587 ftThe curve…

Q: An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI…

A:

Q: Q6. To help improve the safety of at-grade intersection of two roads, the intersection is being…

A: Given Data, G1=+4% (Upgrade)G2= -3% (Downgrade)L1= 138 mStation PVC1=14+47, Elevation PVC1=477m…

Q: 1. A sag vertical curve is shown below: BVC Sta 19+50 EVC Sta 24+50 -3.2% +2.4% EVİ Sta 22+00; Elev…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: A highway curve will pass through a railway and grade. The crossing must be at station 4 + 310 and…

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Q: A 618m equal tangent crest vertical curve has PVC at Sta 19+218 and at elevation 177m. The initial…

A: The gradient is, g1=4.05%g2=-6.26% The PVC station is 19+218. The length is L=618 m. The elevation…