-4% -3% +3% +4% CL 5%
The following figures show the cross-sections at the two ends of a superelevation development length of 165 m. Calculate the RL of inner and outer edge of the pavements at 15m interval. Given that, at the start of superelevation road centre line RL was 200.200m, road lane width is 4.0m and shoulder width is 3.0m. Final superelevation to attain was 5%. Road is in a rising grade of 1.0%. Assume centre-line axis of rotation.
To calculate the Reduced Levels (RL) of the inner and outer edges of the pavements at 15m intervals along the superelevation development length, we can follow these steps:
1. Calculate the initial cross-fall slope (e) at the start of the superelevation:
e = (final superelevation - initial superelevation) / superelevation development length
e = (5% - 0%) / 165m
e = 0.03 or 3%
2. Determine the rate of superelevation change (Δe) per meter:
Δe = e / superelevation development length
Δe = 3% / 165m
Δe = 0.0182% per meter
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