4G 4G 11:33 ANSWERED Tuesday, Dec 10, 2024 ENGINEERING CIVIL-ENGINEERING Problem 6: A 2m square footing supports a 400-mm square column. The column supports an axial dead load of 1250 and an axial Ive load of 1860M. Concrete strength-21MP and steel yield strength (-225MPa Use 25mm bars and 75mm concrete cover (a) Determine the thickness based on wide beam shear (b) Determine the thickness based on punching shar 2.00m nching Expert Answer ● Steps ? ] 200m Pu d U Do 52

4G 4G 11:33 ANSWERED Tuesday, Dec 10, 2024 ENGINEERING CIVIL-ENGINEERING Problem 6: A 2m square footing supports a 400-mm square column. The column supports an axial dead load of 1250 and an axial Ive load of 1860M. Concrete strength-21MP and steel yield strength (-225MPa Use 25mm bars and 75mm concrete cover (a) Determine the thickness based on wide beam shear (b) Determine the thickness based on punching shar 2.00m nching Expert Answer ● Steps ? ] 200m Pu d U Do 52

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter11: Load And Resistance Factor Design (lrfd)

Section: Chapter Questions

Problem 11.3P: Repeat Problem 11.1 based on LRFD using the following factors: load factor for dead load = 1.25 load...

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A continuous foundation is required in a soil where c=10kN/m2, =26, and =19.0kN/m3. The depth of the footing will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (6.10) and Table 6.1.
Redo Problem 16.13 with the following data: gross allowable load = 184,000 lb, = 121 lb/ft3, c = 0, =26, Df = 6.5 ft., and required factor of safety = 2.5. 16.13 A square footing (B B) must carry a gross allowable load of 1160 kN. The base of the footing is to be located at a depth of 2 m below the ground surface. If the required factor of safety is 4.5, determine the size of the footing. Use Terzaghis bearing capacity factors and assume general shear failure of soil. Given: = 17 kN/m3, c = 48 kN/m2, =31.
For the mat in Problem 16.15, what will be the depth, Df, of the mat for FS = 3 against bearing capacity failure? 16.15 Consider a mat foundation with dimensions of 18 m 12 m. The combined dead and live load on the mat is 44.5 MN. The mat is to be placed on a clay with cu = 40.7 kN/m2 and = 17.6 kN/m3. Find the depth, Df, of the mat for a fully compensated foundation.
Redo Problem 16.2 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17 6.2 Refer to Problem 16.1. If a square footing with dimension 2 m 2 m is used instead of the wall footing, what would be the allowable bearing capacity?
Redo Problem 6.2 using the general bearing capacity equation [Eq. (6.28)]. A 5.0 ft wide square footing is placed at 3.0 ft depth within the ground where c = 200 lb/ft2, = 25, and = 115.0 lb/ft3. Determine the ultimate bearing capacity of the footing using Terzaghis bearing capacity equation and the bearing capacity factors from Table 6.1. What is the maximum column load that can be allowed with a factor of safety of 3.0?
Redo Problem 16.4 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17 16.4 Redo Problem 16.1 with the following: = 16.5 kN/m3, cu = 41 kN/m3, =0, Df = 1.5 m, and factor of safety = 5.
Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17
Redo Problem 16.3 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17 16.3 Redo Problem 16.1 with the following: = 115 lb/ft3, c = 1100 lb/ft2, =35, Df = 3.5 ft, B = 5 ft, and factor of safety = 4.
A W1422 acts compositely with a 4-inch-thick floor slab whose effective width b is 90 inches. The beams are spaced at 7 feet 6 inches, and the span length is 30 feet. The superimposed loads are as follows: construction load = 20 psf, partition load = 10 psf, weight of ceiling and light fixtures = 5 psf, and live load = 60 psf, A992 steel is used, and fc=4 ksi. Determine whether the flexural strength is adequate. a. Use LRFD. b. Use ASD.
Refer to Problem 16.13. Design the size of the footing using the modified general ultimate bearing capacity Eq. (16.31). 16.13 A square footing (B B) must carry a gross allowable load of 1160 kN. The base of the footing is to be located at a depth of 2 m below the ground surface. If the required factor of safety is 4.5, determine the size of the footing. Use Terzaghis bearing capacity factors and assume general shear failure of soil. Given: = 17 kN/m3, c = 48 kN/m2, = 31.
Repeat Problem 11.1 based on limit state design, using the factors given in Table 11.4. 11.1 A continuous foundation is required in a soil where , , and . The depth of the footing will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (6.10) and Table 6.1.
Repeat Problem 20.2 based on LRFD using the following factors. Load factor for dead load = 1.25 Load factor for live load = 1.75 Strength reduction factor on the ultimate bearing capacity = 0.50 20.2 A continuous foundation is required in a soil where c = 10 kN/m2, =26 and = 19.0 kN/m3. The depth of the foundation will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (16.3) and Table 16.1.