47. (III) A flat slab of nonconducting material has thickness 2d, which is small compared to its height and breadth. Define the x axis to be along the direction of the slab's thickness with the origin at the center of the slab (Fig. 22-41). If the slab carries a volume charge density PE(x) = -Po in the region -d < x <0 and Pe(x) = +Po in the region 0 < xs +d, determine the electric field E as a function of x in the regions (a) outside the slab, (b) 0 < xs +d, and (c) -d s x < 0. Let po be a positive constant. + +d
47. (III) A flat slab of nonconducting material has thickness 2d, which is small compared to its height and breadth. Define the x axis to be along the direction of the slab's thickness with the origin at the center of the slab (Fig. 22-41). If the slab carries a volume charge density PE(x) = -Po in the region -d < x <0 and Pe(x) = +Po in the region 0 < xs +d, determine the electric field E as a function of x in the regions (a) outside the slab, (b) 0 < xs +d, and (c) -d s x < 0. Let po be a positive constant. + +d
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![47. (III) A flat slab of nonconducting material has thickness 2d,
which is small compared to its height and breadth. Define
the x axis to be along the direction of the slab's thickness
with the origin at the center of the slab (Fig. 22-41).
If the slab carries a volume
charge density PE(x)
the region -d < x <0 and
PE(x) = +po in the region
0 < xs +d, determine the
electric field E as a function of
x in the regions (a) outside the
slab,
= -Po in
(b) 0 < x < +d, and
(c) -d s x < 0. Let po be a
positive constant.
-
+d
FIGURE 22-41](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa11def6c-f018-4b1c-9580-ae0c0b2f13d0%2F1bff0ed2-75fb-4a28-ad18-10b078bb3b24%2F12aoyq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:47. (III) A flat slab of nonconducting material has thickness 2d,
which is small compared to its height and breadth. Define
the x axis to be along the direction of the slab's thickness
with the origin at the center of the slab (Fig. 22-41).
If the slab carries a volume
charge density PE(x)
the region -d < x <0 and
PE(x) = +po in the region
0 < xs +d, determine the
electric field E as a function of
x in the regions (a) outside the
slab,
= -Po in
(b) 0 < x < +d, and
(c) -d s x < 0. Let po be a
positive constant.
-
+d
FIGURE 22-41
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