Find the acceleration in Pm/s2 (1P=1015) for the electron in problem 22.48 a. using a charge density of a = 9.98 µC/m²

College Physics
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Author:Paul Peter Urone, Roger Hinrichs
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Chapter18: Electric Charge And Electric Field
Section: Chapter Questions
Problem 42PE: (a) Find the total electric field at x = 1.00 cm in Figure 18.52(b) given that q =5.00 nC. (b) Find...
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QUESTION 4
Find the acceleration in Pm/s2 (1P=1015) for the electron in problem 22.48.a. using a charge density of a = 9.98 µC/m²
Transcribed Image Text:QUESTION 4 Find the acceleration in Pm/s2 (1P=1015) for the electron in problem 22.48.a. using a charge density of a = 9.98 µC/m²
of 1.00 cm?
48 In Fig. 22-59, an electron (e) is to
be released from rest on the central axis
of a uniformly charged disk of radius R.
The surface charge density on the disk is
+4.00 μC/m². What is the magnitude of
the electron's initial acceleration if it is
released at a distance (a) R, (b) R/100,
and (c) R/1000 from the center of the disk? (d) Why does the ac-
celeration magnitude increase only slightly as the release point is
moved closer to the disk?
Figure 22-59
Problem 48.
Transcribed Image Text:of 1.00 cm? 48 In Fig. 22-59, an electron (e) is to be released from rest on the central axis of a uniformly charged disk of radius R. The surface charge density on the disk is +4.00 μC/m². What is the magnitude of the electron's initial acceleration if it is released at a distance (a) R, (b) R/100, and (c) R/1000 from the center of the disk? (d) Why does the ac- celeration magnitude increase only slightly as the release point is moved closer to the disk? Figure 22-59 Problem 48.
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