Problem 5: A thin rod of length L = 1.9 m lies along the positive y-axis with one end at the origin. The rod carries a uniformly distributed charge of Q1 = 5.2 µC. A point charge Q2 = 10.4 µC is located on the positive x-axis a distance a = 0.45 m from the origin. Refer to the figure. dy |L a Part (a) Consider a thin slice of the rod of thickness dy located a distance y away from the origin. What is the direction of the force on the point charge due to the charge on this thin slice? MultipleChoice: 1) Along the positive x-axis 2) Above the negative x-axis 3) Below the positive x-axis 4) Not enough information to determine 5) There is no force between the point charge and the slice of the rod 6) Above the positive x-axis 7) Below the negative x-axis Part (b) Choose the correct equation for x-component of the force, dFx, on the point charge due to the thin slice of the rod. SchematicChoice : kQ,Q2ady Q1Q2ady kQ1Q2ady dF, L(a² + y²) dF, L(a² + y²)ž dF, L(a² + y²)ž %3D 3 3 Q1Q2ydy kQ1Q2ydy kQ1Q2ydy dF, = L(a² + y²)z dF (a² + y²)z dFx L(a² + y²) 3 3 Part (c) Integrate the correct expression in part (b) over the length of the rod to find the x-component of the net force and calculate its value, in newtons. Numeric : A numeric value is expected and not an expression. Fx = Part (d) Choose the correct equation for the y-component of the force, dFy, on the point charge due to the thin slice of the rod. SchematicChoice : kQ1Q2ady kQ,Q2ydy dF, L(a² + y²)ž kQ1Q2ady dF, dF, 3 3 L(a² + y²)z L(a² + y²)ž kQ1Q2ady L(a² + y²) kQ1Q2ydy dF, = L(a² + y²)ž kQ1Q2ady dF, L(a² + y²) %3D dF, = - 3 Part (e) Integrate the correct expression in part (d) over the length of the rod to find the y-component of the net force and calculate its value, in newtons. Numeric : A numeric value is expected and not an expression. Fy =
Problem 5: A thin rod of length L = 1.9 m lies along the positive y-axis with one end at the origin. The rod carries a uniformly distributed charge of Q1 = 5.2 µC. A point charge Q2 = 10.4 µC is located on the positive x-axis a distance a = 0.45 m from the origin. Refer to the figure. dy |L a Part (a) Consider a thin slice of the rod of thickness dy located a distance y away from the origin. What is the direction of the force on the point charge due to the charge on this thin slice? MultipleChoice: 1) Along the positive x-axis 2) Above the negative x-axis 3) Below the positive x-axis 4) Not enough information to determine 5) There is no force between the point charge and the slice of the rod 6) Above the positive x-axis 7) Below the negative x-axis Part (b) Choose the correct equation for x-component of the force, dFx, on the point charge due to the thin slice of the rod. SchematicChoice : kQ,Q2ady Q1Q2ady kQ1Q2ady dF, L(a² + y²) dF, L(a² + y²)ž dF, L(a² + y²)ž %3D 3 3 Q1Q2ydy kQ1Q2ydy kQ1Q2ydy dF, = L(a² + y²)z dF (a² + y²)z dFx L(a² + y²) 3 3 Part (c) Integrate the correct expression in part (b) over the length of the rod to find the x-component of the net force and calculate its value, in newtons. Numeric : A numeric value is expected and not an expression. Fx = Part (d) Choose the correct equation for the y-component of the force, dFy, on the point charge due to the thin slice of the rod. SchematicChoice : kQ1Q2ady kQ,Q2ydy dF, L(a² + y²)ž kQ1Q2ady dF, dF, 3 3 L(a² + y²)z L(a² + y²)ž kQ1Q2ady L(a² + y²) kQ1Q2ydy dF, = L(a² + y²)ž kQ1Q2ady dF, L(a² + y²) %3D dF, = - 3 Part (e) Integrate the correct expression in part (d) over the length of the rod to find the y-component of the net force and calculate its value, in newtons. Numeric : A numeric value is expected and not an expression. Fy =
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 3 images