Homework Help is Here – Start Your Trial Now!
Science
Chemistry
45). A student hopes to dissolve 0.900 g of Pbl2 in pure water to make 1 L of solution. Will all 0.900 g of Pbl2 dissolve in pure water to make a 1L of solution as hoped by the student? a. All 0.900 g of Pbl2 will dissolve. b. Not all 0.900 g of Pbl2 will dissolve. c. This is way under saturation, so all 0.900 g of Pbl, will dissolve. d. Cannot be predicted

45). A student hopes to dissolve 0.900 g of Pbl2 in pure water to make 1 L of solution. Will all 0.900 g of Pbl2 dissolve in pure water to make a 1L of solution as hoped by the student? a. All 0.900 g of Pbl2 will dissolve. b. Not all 0.900 g of Pbl2 will dissolve. c. This is way under saturation, so all 0.900 g of Pbl, will dissolve. d. Cannot be predicted

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
45). A student hopes to dissolve 0.900 g of Pbl2 in pure water to make 1 L of solution. Will all 0.900 g of Pbl2 dissolve in pure water to make a 1L of solution as hoped by the student? a. All 0.900 g of Pbl2 will dissolve. b. Not all 0.900 g of Pbl2 will dissolve. c. This is way under saturation, so all 0.900 g of Pbl, will dissolve. d. Cannot be predicted
Transcribed Image Text:45). A student hopes to dissolve 0.900 g of Pbl2 in pure water to make 1 L of solution. Will all 0.900 g of Pbl2 dissolve in pure water to make a 1L of solution as hoped by the student? a. All 0.900 g of Pbl2 will dissolve. b. Not all 0.900 g of Pbl2 will dissolve. c. This is way under saturation, so all 0.900 g of Pbl, will dissolve. d. Cannot be predicted
Expert Solution
Step 1

Since the solubility product of PbI2 = 9.8 X 10-9 at 25 oC

And the solubility reaction of PbI2 is

=> PbI2 (s) ------> Pb2+ (aq) + 2 I- (aq)

 

Step 2

Assuming the solubility of PbI2 is s. Hence maximum s concentration of PbI2 will dissolve in water

Hence the concentration of ions formed at equilibrium are 

[Pb2+ ]= concentration of PbI2 dissolved = s 

[I- ] = concentration of PbI2 dissolved X 2 = 2s

Since the solubility product of PbI2 is given by 

Ksp = [Pb2+ ][I- ]2 

Hence substituting the values we get 

9.8 X 10-9 = s X (2s)2 

=> s = maximum concentration of PbI2 that can be dissolved = 0.00135 M

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Concentration Terms
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS