Show all working explaining detailly each step.Answer Q a & b 143 Fig. 1 shows the bone and muscle structure ofa person's arm supporting a 5.0 kg mass inFu5.0kg maie5.0ho20N20N5.0 cm -15 сm15 em35 cm35 cmFig 2Fig 1equilibrium. The forearm is horizontal and isat right angles to the upper arm. Fig. 2 showsthe equivalent mechanical system.FM is the force exerted by the biceps muscleand F is the force at the elbow joint. Theperpendicular distance between the lines ofaction of FM and F, is 5.0 cm.(a) (i) Explain why the 20N force has beenincluded.(ii) State the conditions which must bemet by the forces when the arm is inequilibrium.(b) (i) Calculate the magnitude of the forceFM.(ii) Show that FA has the same magni-tude when the forearm is at 45 to thehorizontal with the upper arm stillvertical.(c) In many athletes the distanue between theelbow joint, E, and the muscle attach-ment, P, is greater than 5.0 cm. Explainhow this is an advantage in lifting andthrowing events.[AEB, '89]

As requested, questions (a) and (b) are answered. Question (a): (i) Apart from mass being lifted…

443 Fig. 1 shows the bone and muscle structure ot a person's arm supporting a 5.0 kg mass in 50kg ma 20N 20N 5.0 15 cm 3 sm 5em 35 cm Fig 1 Fg 2 equilibrium. The forearm is horizontal and is at right angles to the upper arm. Fig. 2 shows the equivalent mechanical system. FM is the force exerted by the biceps muscle and F is the force at the elbow joint. The perpendicular distance between the lines of action of FM and F is 5.0 cm. (a) (1) Explain why the 20N force has been included. (ii) State the conditions which must be met by the forces when the arm is in equilibrium. (b) (i) Calculate the magnitude of the force FM (ii) Show that Fa has the same magni- tude when the forearm is at 45 to the horizontal with the upper arm still vertical.

443 Fig. 1 shows the bone and muscle structure ot a person's arm supporting a 5.0 kg mass in 50kg ma 20N 20N 5.0 15 cm 3 sm 5em 35 cm Fig 1 Fg 2 equilibrium. The forearm is horizontal and is at right angles to the upper arm. Fig. 2 shows the equivalent mechanical system. FM is the force exerted by the biceps muscle and F is the force at the elbow joint. The perpendicular distance between the lines of action of FM and F is 5.0 cm. (a) (1) Explain why the 20N force has been included. (ii) State the conditions which must be met by the forces when the arm is in equilibrium. (b) (i) Calculate the magnitude of the force FM (ii) Show that Fa has the same magni- tude when the forearm is at 45 to the horizontal with the upper arm still vertical.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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