4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources

4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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04 Fill in the Blank Drag and Drop Use the reaction below to determine the mass of oxygen needed to completely react 450.4 grams of butane (C4H10). 2 CH10 13 O2 -----> 8 CO2 10 H20 Molar mass of butane = 1 mole Molar mass of oxygen = 16.00 6. mole 450.4 g of butane = 1 i moles Moles of oxygen needed = 1 i moles Mass of oxygen needed = 1 i grams : 7.747 :: 50.36 :: 1611 : 450.4 : 58.14 : 1522 :32.00 : 42
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