4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources

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4:25 1
.ll LTE
Question 3 of 14
Submit
According to the balanced reaction below, calculate the
moles of NO2 that form when 5.20 x 10-3 | mol of N2O5
completely reacts:
2 N2O5(g) →
4
NO2(g) + O2(g)
STARTING AMOUNT
ADD FACTOR
DELETE
ANSWER
RESET
*( )
х
g NO2
1.30 x 10-3
46.01
mol N2O5
5.20 x 10-3
4
g O2
32.00
0.0208
mol NO2
6.022 x 1023
mol O2
108.02
g N205
2.60 x 10-3
0.0104
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Transcribed Image Text:4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources
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