4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources
4:25 1 .ll LTE Question 3 of 14 Submit According to the balanced reaction below, calculate the moles of NO2 that form when 5.20 x 10-3 | mol of N2O5 completely reacts: 2 N2O5(g) → 4 NO2(g) + O2(g) STARTING AMOUNT ADD FACTOR DELETE ANSWER RESET *( ) х g NO2 1.30 x 10-3 46.01 mol N2O5 5.20 x 10-3 4 g O2 32.00 0.0208 mol NO2 6.022 x 1023 mol O2 108.02 g N205 2.60 x 10-3 0.0104 Tap here or pull up for additional resources
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![4:25 1
.ll LTE
Question 3 of 14
Submit
According to the balanced reaction below, calculate the
moles of NO2 that form when 5.20 x 10-3 | mol of N2O5
completely reacts:
2 N2O5(g) →
4
NO2(g) + O2(g)
STARTING AMOUNT
ADD FACTOR
DELETE
ANSWER
RESET
*( )
х
g NO2
1.30 x 10-3
46.01
mol N2O5
5.20 x 10-3
4
g O2
32.00
0.0208
mol NO2
6.022 x 1023
mol O2
108.02
g N205
2.60 x 10-3
0.0104
Tap here or pull up for additional resources](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fedec9be0-104a-4076-a5ce-81b267ecc4b9%2Fb13f7c5c-c1b1-4d84-aeed-fbea56198f65%2Fuxykvco.png&w=3840&q=75)
Transcribed Image Text:4:25 1
.ll LTE
Question 3 of 14
Submit
According to the balanced reaction below, calculate the
moles of NO2 that form when 5.20 x 10-3 | mol of N2O5
completely reacts:
2 N2O5(g) →
4
NO2(g) + O2(g)
STARTING AMOUNT
ADD FACTOR
DELETE
ANSWER
RESET
*( )
х
g NO2
1.30 x 10-3
46.01
mol N2O5
5.20 x 10-3
4
g O2
32.00
0.0208
mol NO2
6.022 x 1023
mol O2
108.02
g N205
2.60 x 10-3
0.0104
Tap here or pull up for additional resources
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