04 Fill in the Blank Drag and Drop Use the reaction below to determine the mass of oxygen needed to completely react 450.4 grams of butane (C4H10). 2 C.H10 13 O2 --- --> 8 CO2 10 H20 Molar mass of butane = 1 mole Molar mass of oxygen = 16.00 mole 450.4 g of butane = 1 i moles -1 Moles of oxygen needed = 1 i moles Mass of oxygen needed = 1 i grams : 7.747 :: 50.36 : 1611 : 450.4 : 58.14 :: 1522 :32.00

Chemistry
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Chapter1: Chemical Foundations
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04 Fill in the Blank Drag and Drop
Use the reaction below to determine the mass of oxygen needed to completely react 450.4 grams of butane (C4H10).
2 CH10
13 O2
----->
8 CO2
10 H20
Molar mass of butane = 1
mole
Molar mass of oxygen =
16.00
6.
mole
450.4 g of butane = 1
i moles
Moles of oxygen needed = 1
i moles
Mass of oxygen needed = 1
i grams
: 7.747
:: 50.36
:: 1611
: 450.4
: 58.14
: 1522
:32.00
: 42
Transcribed Image Text:04 Fill in the Blank Drag and Drop Use the reaction below to determine the mass of oxygen needed to completely react 450.4 grams of butane (C4H10). 2 CH10 13 O2 -----> 8 CO2 10 H20 Molar mass of butane = 1 mole Molar mass of oxygen = 16.00 6. mole 450.4 g of butane = 1 i moles Moles of oxygen needed = 1 i moles Mass of oxygen needed = 1 i grams : 7.747 :: 50.36 :: 1611 : 450.4 : 58.14 : 1522 :32.00 : 42
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