4:00 Step 1 Step 2 Question 10 of 13 H₂(g) + 2NO(g) → N₂O(g) + H₂O(g) (slow) N₂O(g) + H₂(g) → N₂(g) + H₂O(g) (fast) A) rate= K[H₂] [NO] B) rate = k[H₂]²[NO] rate = = K[H₂] [NO]² D) rate= = K[H₂]²[NO]² Submit rate = K[H₂] [N₂O] Learn More in OpenStax Periodic Table

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.63PAE: The following mechanism is proposed for a reaction: NO + Br2 —* NOBr2 (slow) NOBr2 + NO —»2 NOBr...
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4:00
Step 1
Step 2
Question 10 of 13
H₂(g) + 2NO(g) → N₂O(g) + H₂O(g)
(slow)
N₂O(g) + H₂(g) → N₂(g) + H₂O(g)
(fast)
A) rate= K[H₂] [NO]
B) rate = k[H₂]²[NO]
rate =
= K[H₂] [NO]²
D) rate= = K[H₂]²[NO]²
Submit
rate = K[H₂] [N₂O]
Learn More in OpenStax
Periodic Table
Transcribed Image Text:4:00 Step 1 Step 2 Question 10 of 13 H₂(g) + 2NO(g) → N₂O(g) + H₂O(g) (slow) N₂O(g) + H₂(g) → N₂(g) + H₂O(g) (fast) A) rate= K[H₂] [NO] B) rate = k[H₂]²[NO] rate = = K[H₂] [NO]² D) rate= = K[H₂]²[NO]² Submit rate = K[H₂] [N₂O] Learn More in OpenStax Periodic Table
4:00
What is the rate law for the proposed
mechanism?
Step 1
Question 10 of 13
Step 2
H₂(g) + 2NO(g) N₂O(g) + H₂O(g)
(slow)
N₂O(g) + H₂(g) → N₂(g) + H₂O(g)
(fast)
A) rate = = K[H₂] [NO]
B) rate = K[H₂]²[NO]
Submit
C) rate = K[H₂] [NO]²
LEL 12 NO12
Tap here or pull up for additional resources
Transcribed Image Text:4:00 What is the rate law for the proposed mechanism? Step 1 Question 10 of 13 Step 2 H₂(g) + 2NO(g) N₂O(g) + H₂O(g) (slow) N₂O(g) + H₂(g) → N₂(g) + H₂O(g) (fast) A) rate = = K[H₂] [NO] B) rate = K[H₂]²[NO] Submit C) rate = K[H₂] [NO]² LEL 12 NO12 Tap here or pull up for additional resources
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