= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution
= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
Section: Chapter Questions
Problem 9.46PAE: 9.46 The heat of fusion of pure silicon is 43.4 kJ/mol. How much energy would be needed to melt a...
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![= 40.6
The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap=
kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g).
sys
a. -109 J/K
b. + 406 J/K
c. +109 J/K
d. +11.2 J/K
e. -12 J/K
Give clear
handwritten
Solution](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34fef24c-f066-4e84-b51c-464bc06b0cb5%2F262e17e0-8b9f-4f9f-aee3-b719a6722f71%2F1wxev7n_processed.png&w=3840&q=75)
Transcribed Image Text:= 40.6
The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap=
kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g).
sys
a. -109 J/K
b. + 406 J/K
c. +109 J/K
d. +11.2 J/K
e. -12 J/K
Give clear
handwritten
Solution
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