40 lb30 Ib60 lb1260 1630 lb40 lb247. The three-step pulley shown in Fig. P-247 is nubjected to the given co!Cumpute the value of the resultant couple. Alo determine the forces actiAe riro of the middle pulley that are required to balanee the given system.FIG. P-247.Ans. C = 760 in.-lb counterclorkwine; two 62 -L 1o16"

Answered: Image /qna-images/answer/ceb70e18-b570-4a27-aee0-1bed3d95d323.jpg

Answered: 40 lb 30 Ib 60 lb 12 16"- 60 1b 30 lb…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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F1 Determine the reaction forces for girder G-1. Column A Beam B-1 L1 -0 Beam B-2 F2 Girder G-1 Please round to the nearest one. Reaction force for Girder G-1 (Column A side) = Girder G-2 L1 After the initial calculation, we determined the following information: • The reaction force for Beam B-2 (Girder G-1 side) = 17,890 lbs • The reaction force for Beam B-3 (Girder G-1 side) = 15,685 lbs Reaction force for Girder G-1 (Column B side) = 80 F3 • Live load 50 psf • Dead load: (1) Slab = 50 psf, (2) Deck = 10 psf, (3) Mechanical equipment = 8 psf, (4) Suspended ceiling = 8 psf (5) Beam = 25 lb/ft, (6) Girder = 35 lb/ft • Beam and Girder spacing:: (1) L1 = 14 ft, (2) L2 = 10 ft, (3) L3 = 10 ft Beam B-3 000 000 F4 lbs open lbs F5 L1 Column B Beam B-4 L2 F6 L3 MacBook Air ← F7 F8
What is the force carried by member DE? Select one: a. 402 kN b. 240 kN c. 204 kN d. 420 kN
SCS SHS 2122 Tn PSCS SHS 2122: Lo... Determine the axial force (kN) in each member of the assembly shown below, Member Cross-Sectional Area Modulus of Elasticity AB 1,000 mm2 200 GPa BC 1,500 mm2 200 GPa DB 1,000 mm2 200 GPa C 18KN A 400mm 400mm 00 50 55.00
: For the column shown in Fig.5. Determine the maximum load P it can carry without buckling. lote from the figure on the left that the ends are pinned for buckling, whereas from the figure on the ght the ends are fixed. If Factor of safety 2, Es (200 Gpa) and oy = 180 (MPa).. 2-4) 3m --Y 50mm 200mm
Determine the force in member DI of the loaded truss. Enter a positive number if in tension, negative if in compression. 4L B 5 m Answer: DI = i Save for Later 6L 6L D E 6L -5 m E H |Η 5 m AB=BC=CD= DE = EF = FG 4L L F L G Attempts: 0 of 1 used Submit Answer
A block with a mass of 150-kg is supported by a cable which posses over a 150 mm diameter puley that is attached to a tame as shown in the figure. Determine al forces octing on member BCD ot the trame. 400 mm- 200- mm LOV 70 450 mm
B4
Determine the reactions at the supports. First, determine the equivalent load [kN] as required below and provide the location of each one from A [m]. The distributed load equivalents MUST be ONLY 2. One for the triangular distribution (FR1) and the other for the rectangular distribution (FR2). 6 kN/m Scale: 1 unit = 0.5 m FR1- FR2- Reaction1 (if present – specify [ Reaction2 (if present – specify [ {kN]; Location from A =, {kN]; Location from A = 1), at A = 1), at A = m [kN] [kN] Reaction1 (if present – specify [ Reaction2 (if present – specify [ 1), at B = 1), at B = [kN] [kN]
Question 22 Form the given beam loaded has shown, Ely = MAT + RĄ2² – P(x – )2 +C1 - Ely = 글MA22 + 금RAz' - 공P(z-)3 + Ciz+ Ca 3 + C1a + C2 Let P=58 kN, L = 19 m P в с D -L/3- L/2 -L/2- Determine the bending moment at point A.
What is the internal force in member AB? A. 750 N , T B. 450 N , T C. 750 N , C D. 450 N , CSHOW SOLUTIONS
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