4.Problem 4 Compute the normal tension which will be applied to a tape supported over two supports in order to make the tape equal to its nominal length when supported only at end points. The steel tape is 30-m long and weights 0.84 kg when supported throughout its length under a standard pull of 5.6kg, with the modulus of elasticity of 2 x 106 , and area of 0.06 cm². ст2
4.Problem 4 Compute the normal tension which will be applied to a tape supported over two supports in order to make the tape equal to its nominal length when supported only at end points. The steel tape is 30-m long and weights 0.84 kg when supported throughout its length under a standard pull of 5.6kg, with the modulus of elasticity of 2 x 106 , and area of 0.06 cm². ст2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
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I'm stuck with the process of getting Pn, how do I get it? please see attached photo. If possible, please explain the process. Thank you.

Transcribed Image Text:11:39 PM Fri Oct 15
a 94% |
( Math Solvings
2.2.4.Problem 4
Compute the normal tension which will be applied to a tape supported over two
supports in order to make the tape equal to its nominal length when supported
only at end points. The steel tape is 30-m long and weights 0.84 kg when
supported throughout its length under a standard pull of 5.6kg, with the modulus
kg
of elasticity of 2 x 106 , and area of 0.06 cm².
cm2
Given: W=0.84 kg
L tape -g0m
Por S.lokg
E- 2x10° kg/cm²
Repd:Pr
A
0.06
EA
24 Pn
24 Put
(0.84) Co.00(2x10*)
24
Pa? ( Pa -S.6)
|
P - S.l6 Pú = 3528
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