4.8 Determine the service level moment capacity of the section in Figure P4.1c if the allowable stress for concrete is 0.45 f', and the allowable stress for the reinforcement is 30,000 psi. Use the areas of reinforcement from Problem 4.3. -28". 8"> 8" W f = 6000psi Ec=57000 fpsi = 4415 ksi Es = 29000000psi b = 28in ys:= 2.5in h := 36in d:= hy, 33.5-in = f= 0.45f=2700psi bw = Sin hea = 8in f = 30000psi

4.8 Determine the service level moment capacity of the section in Figure P4.1c if the allowable stress for concrete is 0.45 f', and the allowable stress for the reinforcement is 30,000 psi. Use the areas of reinforcement from Problem 4.3. -28". 8"> 8" W f = 6000psi Ec=57000 fpsi = 4415 ksi Es = 29000000psi b = 28in ys:= 2.5in h := 36in d:= hy, 33.5-in = f= 0.45f=2700psi bw = Sin hea = 8in f = 30000psi

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

nas
kd
1.
b
k:-√√(p-n)² + 2-p-n - p-n-
Msc. = (-k-d-b-(d - kd).
k-d
M₂-4,5 (1-2)
d
3
d
U
f₂
T
jd=d-k
с
(3)
kd
+

4.8 Determine the service level moment capacity of the section in Figure P4.1c if the allowable
stress for concrete is 0.45 f', and the allowable stress for the reinforcement is 30,000 psi. Use the
areas of reinforcement from Problem 4.3.
-28".
8">
8"
W
f = 6000psi
Ec=57000fpsi = 4415 ksi
Es = 29000000psi
b = 28in h := 36in
ys:= 2.5in
dhy, = 33.5-in
f = 0.45 = 2700psi
bw = Sin
hea
= 8in
f = 30000psi

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