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Compute the forces in the concrete and steel. The compression force in the concrete is C. = 0.85 x 5 ksi x 4.54 in. X 16 in. = 309 kips The force in the tension reinforcement is = -60 ksi X 4 in.? = -240 kips Since a = 4.54 in. is greater than d2 = 2.5 in., Eq. (11-13b) is used to compute F2. E2 = (48.7 – 0.85 x 5) x 4 = 178 kips

Compute the forces in the concrete and steel. The compression force in the concrete is C. = 0.85 x 5 ksi x 4.54 in. X 16 in. = 309 kips The force in the tension reinforcement is = -60 ksi X 4 in.? = -240 kips Since a = 4.54 in. is greater than d2 = 2.5 in., Eq. (11-13b) is used to compute F2. E2 = (48.7 – 0.85 x 5) x 4 = 178 kips

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Compute the forces in the concrete and steel. The compression force in the concrete is C. = 0.85 x 5 ksi x 4.54 in. X 16 in. = 309 kips The force in the tension reinforcement is = -60 ksi X 4 in.? = -240 kips Since a = 4.54 in. is greater than d2 = 2.5 in., Eq. (11-13b) is used to compute F2. E2 = (48.7 – 0.85 x 5) x 4 = 178 kips
Transcribed Image Text:Compute the forces in the concrete and steel. The compression force in the concrete is C. = 0.85 x 5 ksi x 4.54 in. X 16 in. = 309 kips The force in the tension reinforcement is = -60 ksi X 4 in.? = -240 kips Since a = 4.54 in. is greater than d2 = 2.5 in., Eq. (11-13b) is used to compute F2. E2 = (48.7 – 0.85 x 5) x 4 = 178 kips
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