4.44 One of the consequences of the law of conservation of energy [Eq. (4.27)] is that a roller coaster cart that begins at rest can never rise higher than its original height'. To overcome this limitation, The Hulk roller coaster at Universal Studios, Orlando, launches the cart up the ramp, such that it has an initial "boost" of kinetic energy (accompanied by the cries of pain from Bruce Banner as he transforms into the Hulk). With what minimum speed must the cart be launched if it is to reach a peak 150.0 m higher than its starting point? Assume iere is no friction between the track and the cart. Given that friction is present a real roller coaster, should you round your answer up or down?
4.44 One of the consequences of the law of conservation of energy [Eq. (4.27)] is that a roller coaster cart that begins at rest can never rise higher than its original height'. To overcome this limitation, The Hulk roller coaster at Universal Studios, Orlando, launches the cart up the ramp, such that it has an initial "boost" of kinetic energy (accompanied by the cries of pain from Bruce Banner as he transforms into the Hulk). With what minimum speed must the cart be launched if it is to reach a peak 150.0 m higher than its starting point? Assume iere is no friction between the track and the cart. Given that friction is present a real roller coaster, should you round your answer up or down?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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according to conservation of energy
energy can never be destroyed only it can transform from one form to other
i.e
kinetic energy can be trasfered to its potential energy and potential energy can be transferred to KE but it cannot be destroyed ideally
if the height of body of mass m is rised by height h from its original position then its potential energy increases by mgh
where g = acceleration due to gravity = 9.81 m/s2
if mass if body is m and speed is v then its KE is given by
KE = 0.5Mv2
here
KE = kinetic energy
PE = potential energy
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