3. Suppose the ski patrol lowers a victim of a ski accident down a slope with angle 0 = 42°, using a rope going parallel up the slope (off to the left in the picture.) The victim and sled have a total mass of 95 kg. The coefficient of friction between the sled and the snow is 0.095. (a) Draw a careful free-body diagram for the sled+person system. Ꮎ

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Only Parts D, E, and F please.

**Physics Problem: Skier on a Slope**

**Scenario:**
Suppose the ski patrol lowers a victim of a ski accident down a slope with an angle \( \theta = 42^\circ \), using a rope going parallel up the slope. The victim and sled have a total mass of 95 kg. The coefficient of friction between the sled and the snow is 0.095.

**Tasks:**

(a) **Free-Body Diagram:**
Draw a thorough free-body diagram for the sled-plus-person system.

*Hint:* Consider the gravitational force, normal force, frictional force, and tension from the rope in your diagram.

**Calculations:**

Calculate the work done by each of the forces as the person is lowered along the slope by 50 m:

(b) **Frictional Force:**
Determine the work done by friction.

(c) **Tension in the Rope:**
Calculate the work done by the rope.

(d) **Gravitational Force:**
Find the work done by the gravitational force.

(e) **Normal Force:**
Evaluate the work done by the normal force.

(f) **Total Work:**
Compute the total work done on the person/sled by all the forces.

**Explanation of the Diagram:**

The diagram accompanying this problem depicts a snow-covered slope with a sled being lowered by a rope. The angle \( \theta \) represents the inclination of the slope with horizontal. This angle is crucial in resolving forces into components parallel and perpendicular to the slope.
Transcribed Image Text:**Physics Problem: Skier on a Slope** **Scenario:** Suppose the ski patrol lowers a victim of a ski accident down a slope with an angle \( \theta = 42^\circ \), using a rope going parallel up the slope. The victim and sled have a total mass of 95 kg. The coefficient of friction between the sled and the snow is 0.095. **Tasks:** (a) **Free-Body Diagram:** Draw a thorough free-body diagram for the sled-plus-person system. *Hint:* Consider the gravitational force, normal force, frictional force, and tension from the rope in your diagram. **Calculations:** Calculate the work done by each of the forces as the person is lowered along the slope by 50 m: (b) **Frictional Force:** Determine the work done by friction. (c) **Tension in the Rope:** Calculate the work done by the rope. (d) **Gravitational Force:** Find the work done by the gravitational force. (e) **Normal Force:** Evaluate the work done by the normal force. (f) **Total Work:** Compute the total work done on the person/sled by all the forces. **Explanation of the Diagram:** The diagram accompanying this problem depicts a snow-covered slope with a sled being lowered by a rope. The angle \( \theta \) represents the inclination of the slope with horizontal. This angle is crucial in resolving forces into components parallel and perpendicular to the slope.
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