(4.2, Similar to For Practice 4.2) Write balanced equation for the combustion of hexane (C6H14) in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water. The smallest possible set of whole-number coefficients has been used. What is the coefficient of C6H14 when the reaction is balanced? O 3 04 0 1 O 2
(4.2, Similar to For Practice 4.2) Write balanced equation for the combustion of hexane (C6H14) in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water. The smallest possible set of whole-number coefficients has been used. What is the coefficient of C6H14 when the reaction is balanced? O 3 04 0 1 O 2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Combustion Reaction of Hexane
**Example Question:**
(4.2, Similar to For Practice 4.2) Write a balanced equation for the combustion of hexane (\( \text{C}_6\text{H}_{14} \)) in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water. The smallest possible set of whole-number coefficients has been used.
**Question:**
What is the coefficient of \( \text{C}_6\text{H}_{14} \) when the reaction is balanced?
---
**Answer Options:**
- ○ 3
- ○ 4
- ○ 1
- ○ 2
### Detailed Explanation:
The balanced chemical equation for the combustion of hexane (\( \text{C}_6\text{H}_{14} \)) is as follows:
\[ \text{2 C}_6\text{H}_{14} + 19 \text{O}_2 \rightarrow 12 \text{CO}_2 + 14 \text{H}_2\text{O} \]
To balance the equation, we follow these steps:
1. **Write the unbalanced equation:**
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
2. **Balance the carbon atoms:**
- There are 6 carbon atoms in \( \text{C}_6\text{H}_{14} \), so we need 6 CO₂ molecules on the products side:
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow 6 \text{CO}_2 + \text{H}_2\text{O} \]
3. **Balance the hydrogen atoms:**
- There are 14 hydrogen atoms in \( \text{C}_6\text{H}_{14} \), so we need 7 \( \text{H}_2\text{O} \) molecules on the products side:
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow 6 \text{CO}_2 + 7 \text{H}_2\text{O} \]
4. **Balance the oxygen atoms:**
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6aa13af-b0b4-4b84-a222-8b6a152716db%2F04903a8f-7d28-4657-8d2f-5bc670dadc74%2Fism186e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Combustion Reaction of Hexane
**Example Question:**
(4.2, Similar to For Practice 4.2) Write a balanced equation for the combustion of hexane (\( \text{C}_6\text{H}_{14} \)) in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water. The smallest possible set of whole-number coefficients has been used.
**Question:**
What is the coefficient of \( \text{C}_6\text{H}_{14} \) when the reaction is balanced?
---
**Answer Options:**
- ○ 3
- ○ 4
- ○ 1
- ○ 2
### Detailed Explanation:
The balanced chemical equation for the combustion of hexane (\( \text{C}_6\text{H}_{14} \)) is as follows:
\[ \text{2 C}_6\text{H}_{14} + 19 \text{O}_2 \rightarrow 12 \text{CO}_2 + 14 \text{H}_2\text{O} \]
To balance the equation, we follow these steps:
1. **Write the unbalanced equation:**
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
2. **Balance the carbon atoms:**
- There are 6 carbon atoms in \( \text{C}_6\text{H}_{14} \), so we need 6 CO₂ molecules on the products side:
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow 6 \text{CO}_2 + \text{H}_2\text{O} \]
3. **Balance the hydrogen atoms:**
- There are 14 hydrogen atoms in \( \text{C}_6\text{H}_{14} \), so we need 7 \( \text{H}_2\text{O} \) molecules on the products side:
\[ \text{C}_6\text{H}_{14} + \text{O}_2 \rightarrow 6 \text{CO}_2 + 7 \text{H}_2\text{O} \]
4. **Balance the oxygen atoms:**
-
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