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то Figure P4.18 RS Rp V 4.18 The ac equivalent circuit of a common-source amplifier is shown in Fig- ure P4.18. The small-signal parameters of the transistor are 8 = 2 mA/V and r = ∞o. (a) The voltage gain is found to be A, = Vo/V₁ = -15 with Rs = 0. What is the value of RD? (b) A source resistor Rs is inserted. Assuming the transistor parameters do not change, what is the value of Rs if the voltage gain is reduced to A₂ = -5.

то Figure P4.18 RS Rp V 4.18 The ac equivalent circuit of a common-source amplifier is shown in Fig- ure P4.18. The small-signal parameters of the transistor are 8 = 2 mA/V and r = ∞o. (a) The voltage gain is found to be A, = Vo/V₁ = -15 with Rs = 0. What is the value of RD? (b) A source resistor Rs is inserted. Assuming the transistor parameters do not change, what is the value of Rs if the voltage gain is reduced to A₂ = -5.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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то Figure P4.18 RS Rp V
Transcribed Image Text:то Figure P4.18 RS Rp V
4.18 The ac equivalent circuit of a common-source amplifier is shown in Fig- ure P4.18. The small-signal parameters of the transistor are 8 = 2 mA/V and r = ∞o. (a) The voltage gain is found to be A, = Vo/V₁ = -15 with Rs = 0. What is the value of RD? (b) A source resistor Rs is inserted. Assuming the transistor parameters do not change, what is the value of Rs if the voltage gain is reduced to A₂ = -5.
Transcribed Image Text:4.18 The ac equivalent circuit of a common-source amplifier is shown in Fig- ure P4.18. The small-signal parameters of the transistor are 8 = 2 mA/V and r = ∞o. (a) The voltage gain is found to be A, = Vo/V₁ = -15 with Rs = 0. What is the value of RD? (b) A source resistor Rs is inserted. Assuming the transistor parameters do not change, what is the value of Rs if the voltage gain is reduced to A₂ = -5.
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