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4.15 Determine the gain G = VL/vs _for the circuit in Fig. P4.15 and specify the linear range of v, for R1 = 4 k2. O Vec = 6 V Vo 4 k2 UL 5 ΚΩ 70 k 20 kΩ R1. Us $10 k2 Figure P4.15: Circuit for Problems 4.15 and 4.16.

4.15 Determine the gain G = VL/vs _for the circuit in Fig. P4.15 and specify the linear range of v, for R1 = 4 k2. O Vec = 6 V Vo 4 k2 UL 5 ΚΩ 70 k 20 kΩ R1. Us $10 k2 Figure P4.15: Circuit for Problems 4.15 and 4.16.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**4.15** Determine the gain \( G = v_L / v_s \) for the circuit in **Fig. P4.15** and specify the linear range of \( v_s \) for \( R_L = 4 \, \text{k}\Omega \). **Figure P4.15**: Circuit for Problems 4.15 and 4.16. --- **Circuit Description:** - The circuit features an operational amplifier (op-amp) with a positive power supply \( V_{cc} = 6 \, \text{V} \). - There are resistors connected as follows: - A \( 5 \, \text{k}\Omega \) resistor connected to the input voltage source \( v_s \). - A \( 20 \, \text{k}\Omega \) resistor connected to ground. - The op-amp has a non-inverting input connected to the node between the \( 5 \, \text{k}\Omega \) and \( 20 \, \text{k}\Omega \) resistors. - The op-amp's output \( v_0 \) is connected to a feedback loop via a \( 4 \, \text{k}\Omega \) resistor. - A \( 70 \, \text{k}\Omega \) resistor is connected from the op-amp’s inverting input to the junction of the \( 4 \, \text{k}\Omega \) resistor. - A \( 10 \, \text{k}\Omega \) resistor is connected to ground from the op-amp’s inverting input. - The load resistor \( R_L = 4 \, \text{k}\Omega \) is connected between the output \( v_L \) and ground. **Analysis Objective:** The task is to calculate the gain \( G = v_L / v_s \) for the given circuit configuration and to determine the linear range for \( v_s \), ensuring that the op-amp operates within its linear region.
Transcribed Image Text:**4.15** Determine the gain \( G = v_L / v_s \) for the circuit in **Fig. P4.15** and specify the linear range of \( v_s \) for \( R_L = 4 \, \text{k}\Omega \). **Figure P4.15**: Circuit for Problems 4.15 and 4.16. --- **Circuit Description:** - The circuit features an operational amplifier (op-amp) with a positive power supply \( V_{cc} = 6 \, \text{V} \). - There are resistors connected as follows: - A \( 5 \, \text{k}\Omega \) resistor connected to the input voltage source \( v_s \). - A \( 20 \, \text{k}\Omega \) resistor connected to ground. - The op-amp has a non-inverting input connected to the node between the \( 5 \, \text{k}\Omega \) and \( 20 \, \text{k}\Omega \) resistors. - The op-amp's output \( v_0 \) is connected to a feedback loop via a \( 4 \, \text{k}\Omega \) resistor. - A \( 70 \, \text{k}\Omega \) resistor is connected from the op-amp’s inverting input to the junction of the \( 4 \, \text{k}\Omega \) resistor. - A \( 10 \, \text{k}\Omega \) resistor is connected to ground from the op-amp’s inverting input. - The load resistor \( R_L = 4 \, \text{k}\Omega \) is connected between the output \( v_L \) and ground. **Analysis Objective:** The task is to calculate the gain \( G = v_L / v_s \) for the given circuit configuration and to determine the linear range for \( v_s \), ensuring that the op-amp operates within its linear region.
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